The Divinity of the Vedas, The Power of Knowledge — Vidaara
वेदों की दिव्यता, विद्या की शक्ति — विदारा
Conceived, Designed & Developed BySachin Sharma
The MI of a uniform rod of mass $M$ and length $L$ about an axis perpendicular through its centre is:
A solid cylinder rolls without slipping with KE $30$ J. Its translational KE is:
The angular momentum of a particle moving along a straight line with constant velocity, about a point not on the line:
The radius of gyration of a uniform rod about a perpendicular axis through its end is:
A wheel of MI $4$ kg·m² is subjected to a torque of $10$ N·m for $4$ s. The change in angular velocity:
The angular momentum of a system is conserved when:
A solid sphere and a hollow sphere of same mass and radius roll without slipping. Ratio of their KE for same $v_{cm}$:
The MI of a thin ring about a diameter is:
Two particles of equal masses $m$ are at $(0, 0)$ and $(a, 0)$. Position of CM:
A pulley of MI $2$ kg·m² and radius $0.1$ m has a string with a $1$ kg mass attached. Acceleration of the mass ($g = 10$):
A wheel rotating at $300$ rpm slows to $60$ rpm uniformly in $20$ s. Angular deceleration in rad/s² (rounded):
A solid sphere rolls down an incline of $\sin\theta = 0.7$. Acceleration (m/s², $g = 10$, rounded):
A disc of mass $1$ kg, radius $0.2$ m rotates at $10$ rad/s. Its angular momentum (in $10^{-2}$ kg·m²/s units):
Assertion (A): When a planet revolves around the sun, its angular momentum is conserved. Reason (R): The gravitational force on the planet acts along the radial direction; hence torque is zero.
Assertion (A): Rolling friction is less than sliding friction. Reason (R): A body rolling on a surface has its contact point instantaneously at rest.
Vidaara uses essential cookies to run the site and, with your consent, optional cookies to understand how learners use Vidaara so we can improve it. We never sell your data. Read our Cookie Policy and Privacy Policy.