Let y = ( x 2 + 5) dx = dx ( x 2 + 5) = ( x 2 + 5) dx ( x 2 + 5) = ( x 2 + 5)(2x + 0) = 2x ( x 2 + 5) therefore dx = ( x 2 + 5)(2x + 0) = 2x ( x 2 + 5)

Continuity and Differentiability — Class 12 Maths Solution

ncert exercise SA NCERT Ex.5.2 ,Q.1,Page 166

Question

$sin(x^2 + 5)$

Step-by-step Solution

Let $y = \sin ({x^2} + 5)$

$\Rightarrow$ $\cfrac{{dy}}{{dx}} = \cfrac{d}{{dx}}\sin ({x^2} + 5) = \cos ({x^2} + 5)\cfrac{d}{{dx}}({x^2} + 5)$

$= \cos ({x^2} + 5)(2x + 0) = 2x\cos ({x^2} + 5)$

therefore $\frac{dy}{dx}=\cos ({x^2} + 5)(2x + 0) = 2x\cos ({x^2} + 5)$

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