If A is a square matrix such that $A^2 = A$, then ${(I + A)^3} - 7A$is equal to
- (a) A
- (b) $I - A$
- (c) I
- (d) 3A
If A is a square matrix such that $A^2 = A$, then ${(I + A)^3} - 7A$is equal to
.:
Option c is correct
We have $A^2 = A$
Now, ${(I + A)^3} - 7A = {I^3} + {A^3} + 3IA(I + A) - 7A$
$= I + {A^2} + 3A(I + A) - 7A = I + {A^2} + 3A + 3{A^2} - 7A$
$= I + 4{A^2} - 4A = I + 4A - 4A = I$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Matrices. Curated by Sachin Sharma. Free for all students.