If A and B are events such that P(A) = 0.4,P(B) = 0.3 and P(A B) = 0.5 , then P ( B A ) equals to

Here, P(A) = 0.4,P(B) = 0.3 and P(A B) = 0.5 P(A B) = 0.4 + 0.3 - 0.5 = 0.2 P ( B A ) = P(A) - P(A B) = 0.4 - 0.2 = 0.2 = 5

Probability — Class 12 Maths Solution

exemplar objective MCQ NCERT,Exemp,Q.63,Page.280

Question

If A and B are events such that $P(A) = 0.4,P(B) = 0.3$ and $P(A \cup B) = 0.5$, then $P\left( {{B^\prime } \cap A} \right)$ equals to

Step-by-step Solution

Here, $P(A) = 0.4,P(B) = 0.3$ and $P(A \cup B) = 0.5$

$\Rightarrow$ $P(A \cap B) = 0.4 + 0.3 - 0.5 = 0.2$
$\therefore$ $P\left( {{B^\prime } \cap A} \right) = P(A) - P(A \cap B)$

$= 0.4 - 0.2 = 0.2 = \frac{1}{5}$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Probability. Curated by Sachin Sharma. Free for all students.