Probability — Class 12 Maths Solution

exemplar objective MCQ NCERT,Exemp,Q.68,Page.281
Question

If A and B are such events that $P(A) > 0$ and $P(B) \ne 1$, then $P\left( {{A^\prime }/{B^\prime }} \right)$ equals to

  • (a) $1 - P(A/B)$
  • (b) $1 - P\left( {{A^\prime }/B} \right)$
  • (c) $\frac{{1 - P(A \cup B)}}{{P\left( {{B^\prime }} \right)}}$ ✓ Correct
  • (d) $P\left( {{A^\prime }} \right)/P\left( {{B^\prime }} \right)$
Step-by-step Solution
Correct answer: option (c)

and $P(B) \ne 1$
$P\left( {{A^\prime }/{B^\prime }} \right) = \frac{{P\left( {{A^\prime } \cap {B^\prime }} \right)}}{{P\left( {{B^\prime }} \right)}} = \frac{{1 - P(A \cup B)}}{{P\left( {{B^\prime }} \right)}}$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Probability. Curated by Sachin Sharma. Free for all students.