Relations and Functions — Class 12 Maths Solution

exemplar objective MCQ NCERT Exemp.Q.46,Page 16
Question

If $f:R \to R$ be defined by $f(x) = \left\{ {\begin{array}{llllllllllllllllllll}{2x:x > 3}\\{{x^2}:1 < x \le 3}\\{3x:x \le 1}\end{array}} \right.$.

Then, $f( - 1) + f(2) + f(4)$ is

  • (a) 9 ✓ Correct
  • (b) 14
  • (c) 5
  • (d) None of these
Step-by-step Solution
Correct answer: option (a)

It is given that,, $f(x) = \left\{ {\begin{array}{llllllllllllllllllll}{2x:x > 3}\\{{x^2}:1 < x \le 3}\\{3x:x \le 1}\end{array}} \right.$

$f( - 1) + f(2) + f(4) = 3( - 1) + {(2)^2} + 2 \times 4$

$= - 3 + 4 + 8 = 9$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Relations and Functions. Curated by Sachin Sharma. Free for all students.