Three Dimensional Geometry — Class 12 Maths Solution

As the required line is parallel to the line

$\cfrac{{x + 3}}{3} = \cfrac{{y - 4}}{5} = \cfrac{{z + 8}}{6}$,

therefore , the line has direction ratios $< 3,5,6 >$.

Also, the line passes through $( - 2,4, - 5)$.

therefore , the equation of the line in (cartesian form) is

$\cfrac{{x - ( - 2)}}{3} = \cfrac{{y - 4}}{5} = \cfrac{{z - ( - 5)}}{6} \Rightarrow \cfrac{{x + 2}}{3}$

$= \cfrac{{y - 4}}{5} = \cfrac{{z + 5}}{6}$