Vector Algebra — Class 12 Maths Solution

exemplar objective MCQ NCERT,Exemp,Q.No.20,Page.217
Question

The position vector of the point which divides the join of points $2\overrightarrow {\rm{a}} - 3\overrightarrow {\rm{b}}$ and $\overrightarrow {\rm{a}} + \overrightarrow {\rm{b}}$ in the ratio 3: 1, is

  • (a) $\frac{{3\overrightarrow {\rm{a}} - 2\overrightarrow {\rm{b}} }}{2}$
  • (b) $\frac{{7\overrightarrow {\rm{a}} - 8\overrightarrow {\rm{b}} }}{4}$
  • (c) $\frac{{3\vec a}}{4}$
  • (d) $\frac{{5\vec a}}{4}$ ✓ Correct
Step-by-step Solution
Correct answer: option (d)

Let the position vector of the point $R$ divides the join of points

$2\overrightarrow {\rm{a}} - 3\overrightarrow {\rm{b}}$ and $\overrightarrow {\rm{a}} + \overrightarrow {\rm{b}}$.

$\therefore$ Position vector $R = \frac{{3(\overrightarrow {\rm{a}} + \overrightarrow {\rm{b}} ) + 1(2\overrightarrow {\rm{a}} - 3\overrightarrow {\rm{b}} )}}{{3 + 1}}$

Since, the position vector of a point $R$ dividing the line segment joining the points $P$ and $Q$,

whose position vectors are $\overrightarrow {\rm{p}}$ and $\overrightarrow {\rm{q}}$

in the ratio $m:n$ internally, is given by $\frac{{m\vec q + n\vec p}}{{m + n}}$.

$\therefore$ $R = \frac{{5\vec a}}{4}$

NCERT & Exemplar solution for CBSE Class 12 Mathematics, Vector Algebra. Curated by Sachin Sharma. Free for all students.