Multiple Choice
Question 1
Let f(x) = x^3 + x + 1. If g is the inverse of f, what is g'(1)?
A
1
B
1/2
C
1/4
D
2
Solution: f(0) = 1, so g(1) = 0. f'(x) = 3x^2 + 1, so f'(0) = 1. Then g'(1) = 1/f'(0) = 1/1 = 1.
Question 2
Suppose f(1) = 4 and f'(1) = 2. If g = f^(-1), what is g'(4)?
A
1/2
B
2
C
1/4
D
4
Solution: g'(4) = 1 / f'(g(4)) = 1 / f'(1) = 1/2, since g(4) = 1.
Question 3
A differentiable function f has an inverse g. A table shows f(3) = 7 and f'(3) = 1/2. What is g'(7)?
A
2
B
1/2
C
-2
D
7
Solution: g'(7) = 1 / f'(g(7)) = 1 / f'(3) = 1 / (1/2) = 2.
Question 4
If f(x) = e^x, and g is its inverse, what is g'(x)?
A
1/x
B
e^x
C
-1/x
D
ln(x)
Solution: The inverse of e^x is ln(x), whose derivative is 1/x. Equivalently, g'(x) = 1/f'(g(x)) = 1/e^(ln x) = 1/x.
Question 5
What is d/dx [ arctan(2x) ]?
A
2 / (1 + 4x^2)
B
1 / (1 + 4x^2)
C
2 / (1 + 2x^2)
D
2 / (1 + x^2)
Solution: By the Chain Rule, d/dx arctan(u) = u'/(1 + u^2). With u = 2x, the result is 2 / (1 + 4x^2).
Question 6
What is d/dx [ arcsin(x^2) ]?
A
2x / sqrt(1 - x^4)
B
1 / sqrt(1 - x^4)
C
2x / sqrt(1 - x^2)
D
2x / (1 + x^4)
Solution: By the Chain Rule, d/dx arcsin(u) = u'/sqrt(1 - u^2). With u = x^2, u' = 2x and u^2 = x^4, giving 2x / sqrt(1 - x^4).
Question 7
What is the value of d/dx [ arctan(x) ] at x = 1?
A
1/2
B
1
C
1/4
D
2
Solution: d/dx arctan(x) = 1/(1 + x^2). At x = 1, this equals 1/(1 + 1) = 1/2.
Question 8
What is d/dx [ arcsin(x/3) ]?
A
1 / sqrt(9 - x^2)
B
1 / (3 sqrt(1 - x^2))
C
3 / sqrt(9 - x^2)
D
1 / sqrt(1 - x^2/9)
Solution: d/dx arcsin(u) = u'/sqrt(1 - u^2) with u = x/3, u' = 1/3. This gives (1/3)/sqrt(1 - x^2/9) = (1/3)/(sqrt(9 - x^2)/3) = 1/sqrt(9 - x^2).
Question 9
What is d/dx [ arccos(2x) ]?
A
-2 / sqrt(1 - 4x^2)
B
2 / sqrt(1 - 4x^2)
C
-1 / sqrt(1 - 4x^2)
D
-2 / (1 + 4x^2)
Solution: d/dx arccos(u) = -u'/sqrt(1 - u^2). With u = 2x, u' = 2, giving -2 / sqrt(1 - 4x^2).
Question 10
What is d/dx [ 3 arcsin(x) ]?
A
3 / sqrt(1 - x^2)
B
1 / sqrt(1 - x^2)
C
3 / (1 + x^2)
D
-3 / sqrt(1 - x^2)
Solution: The constant multiple stays: 3 * d/dx arcsin(x) = 3 / sqrt(1 - x^2).
Question 11
What is d/dx [ x^2 sin(x) ]?
A
2x sin(x) + x^2 cos(x)
B
2x cos(x)
C
2x sin(x) - x^2 cos(x)
D
x^2 cos(x)
Solution: By the Product Rule: (2x) sin(x) + x^2 (cos x) = 2x sin(x) + x^2 cos(x).
Question 12
What is d/dx [ sin(x) / x ]?
A
(x cos(x) - sin(x)) / x^2
B
cos(x) / 1
C
(sin(x) - x cos(x)) / x^2
D
cos(x) / x^2
Solution: By the Quotient Rule: (x * cos(x) - sin(x) * 1) / x^2 = (x cos(x) - sin(x)) / x^2.
Question 13
What is d/dx [ x e^x ]?
A
e^x (x + 1)
B
e^x
C
x e^x
D
e^x (x - 1)
Solution: By the Product Rule: (1) e^x + x e^x = e^x(1 + x) = e^x(x + 1).
Question 14
Which rule is most appropriate to differentiate f(x) = (3x + 2)^10?
A
Chain Rule
B
Product Rule
C
Quotient Rule
D
Power Rule only
Solution: The function is a composite (an inner linear function raised to a power), so the Chain Rule is used: 10(3x + 2)^9 * 3.
Question 15
What is d/dx [ (x^2 + 1)(x^3 - 2) ]?
A
5x^4 + 3x^2 - 4x
B
6x^2 - 4x
C
5x^4 - 4x
D
2x(x^3 - 2)
Solution: Product Rule: (2x)(x^3 - 2) + (x^2 + 1)(3x^2) = 2x^4 - 4x + 3x^4 + 3x^2 = 5x^4 + 3x^2 - 4x.
Question 16
What is d/dx [ tan(x) / x ]?
A
(x sec^2(x) - tan(x)) / x^2
B
sec^2(x) / x^2
C
(tan(x) - x sec^2(x)) / x^2
D
sec^2(x)
Solution: Quotient Rule: (x * sec^2(x) - tan(x) * 1) / x^2 = (x sec^2(x) - tan(x)) / x^2.
Question 17
What is d/dx [ sqrt(x) sin(x) ]?
A
sin(x)/(2 sqrt(x)) + sqrt(x) cos(x)
B
sqrt(x) cos(x)
C
cos(x)/(2 sqrt(x))
D
sin(x)/(2 sqrt(x))
Solution: Product Rule with d/dx sqrt(x) = 1/(2 sqrt(x)): (1/(2 sqrt(x))) sin(x) + sqrt(x) cos(x).
Question 18
To differentiate f(x) = cos(3x) / e^x, which combination of rules is required?
A
Quotient Rule and Chain Rule
B
Product Rule only
C
Power Rule only
D
Chain Rule only
Solution: The function is a quotient (needs the Quotient Rule), and the numerator cos(3x) is composite (needs the Chain Rule).
Question 19
If f(x) = e^(2x), what is f''(x)?
A
4e^(2x)
B
2e^(2x)
C
e^(2x)
D
4x e^(2x)
Solution: f'(x) = 2e^(2x), and f''(x) = 4e^(2x).
Question 20
If f(x) = cos(x), what is the fourth derivative f''''(x)?
A
cos(x)
B
-cos(x)
C
sin(x)
D
-sin(x)
Solution: Derivatives cycle: f' = -sin(x), f'' = -cos(x), f''' = sin(x), f'''' = cos(x).