Problem of the Day
Today's maths challenge
🔥0-day streak
Differentiate $\;y = x^2 \sin x$ with respect to $x$.
Hint: Use the product rule: $(uv)' = u'v + uv'$.
Answer: 2x sin x + x² cos x
- Let $u = x^2$ and $v = \sin x$, so $u' = 2x$ and $v' = \cos x$.
- Product rule: $\dfrac{dy}{dx} = u'v + uv' = 2x\sin x + x^2\cos x$.
Answer: $\dfrac{dy}{dx} = 2x\sin x + x^2\cos x$.
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