Hydrogen
Hydrogen for JEE Main & Advanced
Hydrogen — Position, Isotopes, Preparation
Position in Periodic Table and IsotopesTopic 1
Hydrogen ($Z = 1$, configuration $1s^1$) is unique — it shows similarities with both alkali metals (Group 1) and halogens (Group 17). Its position in the periodic table is debated.
Resemblance with Alkali Metals:
- Electronic configuration: $ns^1$
- Forms unipositive ion (H⁺)
- Forms halides (HCl like NaCl)
- Reducing nature
Resemblance with Halogens:
- One electron short of noble gas configuration
- Forms diatomic molecule (H₂)
- Forms uninegative ion (H⁻, hydride)
- Combines with metals and non-metals
Unique Features:
- Smallest atom
- H⁺ is just a bare proton (no electrons) — different from any other cation
- Lower IE than expected for halogens
- Higher IE than alkali metals
Isotopes of Hydrogen:
| Isotope | Symbol | Composition | Abundance | Properties |
|---|---|---|---|---|
| Protium | $^1H$ or H | $1p, 1e, 0n$ | $99.98\%$ | Common hydrogen |
| Deuterium | $^2H$ or D | $1p, 1e, 1n$ | $0.015\%$ | Heavy hydrogen |
| Tritium | $^3H$ or T | $1p, 1e, 2n$ | Trace ($10^{-15}\%$) | Radioactive ($\beta^-$ emitter, $t_{1/2} = 12.3$ years) |
Heavy Water (D₂O): $D_2O$ (deuterium oxide). Properties differ slightly from $H_2O$:
- Higher BP ($101.4°$C vs $100°$C)
- Higher MP ($3.8°$C vs $0°$C)
- Higher density ($1.106$ g/mL vs $1.000$)
- Used as moderator in nuclear reactors (slows neutrons without absorbing them)
- Toxic in large amounts to organisms
Ortho and Para Hydrogen:
- Ortho: nuclear spins parallel (75% at room T)
- Para: nuclear spins antiparallel (25% at room T)
- At low T (below 20 K), all converts to para (more stable)
Compare hydrogen with alkali metals and halogens.
Show solution
Similarities with alkali metals: $ns^1$ config, forms M⁺, reducing. Similarities with halogens: forms H⁻, diatomic H₂, one e⁻ short of noble gas. Differences: H is non-metal, gas at RT; alkali metals are solid metals. H is not as electronegative as halogens. Therefore, H is uniquely placed — neither pure alkali nor pure halogen.
Final Answer: H shows dual character but matches neither group fully.
Why is D₂O used as a moderator in nuclear reactors?
Show solution
$D_2O$ slows down fast neutrons (released in fission) by elastic collision. Since D has similar mass to neutron, it effectively slows neutrons. Unlike H, D does not absorb neutrons much — keeping neutron flux available for further fission.
Final Answer: Moderates (slows) neutrons without absorbing them.
Hydrogen resembles alkali metals due to:
Tritium is:
Mass number of deuterium:
Heavy water is used in:
Ortho-hydrogen at room temperature has fraction:
Preparation and Properties of HydrogenTopic 2
Laboratory Preparation:
- Action of dilute HCl or H₂SO₄ on Zn:
$$\text{Zn} + 2\text{HCl} \to \text{ZnCl}_2 + \text{H}_2$$ $$\text{Zn} + \text{H}_2\text{SO}_4 \to \text{ZnSO}_4 + \text{H}_2$$
- (Pure H₂): Action of NaOH on Al or Zn:
$$2\text{Al} + 6\text{NaOH} \to 2\text{Na}_3\text{AlO}_3 + 3\text{H}_2$$
- Action of pure water on Na (violent — not preferred):
$$2\text{Na} + 2\text{H}_2\text{O} \to 2\text{NaOH} + \text{H}_2$$
Industrial Preparation:
| Method | Reaction | Notes |
|---|---|---|
| Bosch process | $C + H_2O \to CO + H_2$ (water gas); then $CO + H_2O \to CO_2 + H_2$ on Fe catalyst | High T |
| Lane process | $3\text{Fe} + 4\text{H}_2\text{O} \to \text{Fe}_3\text{O}_4 + 4\text{H}_2$ (alternate steam pass) | $1000$ K |
| From hydrocarbons (steam reforming) | $\text{CH}_4 + \text{H}_2\text{O} \to \text{CO} + 3\text{H}_2$ | Ni catalyst, $1100$ K |
| Electrolysis of water | $2\text{H}_2\text{O} \to 2\text{H}_2 + \text{O}_2$ | Trace acid/base added |
Physical Properties:
- Colorless, odorless, tasteless, non-toxic gas
- Lightest gas (M = 2)
- BP $-253°$C, MP $-259°$C
- Slightly soluble in water; very soluble in metals like Pd (used for purification)
Chemical Properties:
- Combustion: $2H_2 + O_2 \to 2H_2O + \text{heat}$ (used in rockets; produces water vapor only — clean fuel)
- With halogens: $H_2 + X_2 \to 2HX$. Reactivity: F > Cl > Br > I.
- With nitrogen (Haber): $N_2 + 3H_2 \rightleftharpoons 2NH_3$ (high P, T, Fe catalyst)
- With metals (hydrides): $2\text{Na} + H_2 \to 2\text{NaH}$
- Reducing agent: Reduces metal oxides ($\text{CuO} + H_2 \to \text{Cu} + \text{H}_2\text{O}$)
- Hydrogenation: Catalytic addition to unsaturated C=C and C=O (Ni, Pd, Pt catalysts)
Uses of Hydrogen:
- Hydrogenation of oils → vanaspati ghee
- Ammonia synthesis (Haber)
- Production of methanol ($\text{CO} + 2H_2 \to \text{CH}_3\text{OH}$)
- Rocket fuel (with O₂)
- Atomic hydrogen torch (welding metals; very high temperature)
- Hydrogen as fuel (zero emissions; fuel cell)
Predict product: $\text{Cu(s)} + H_2 \xrightarrow{\Delta} ?$
Show solution
At ordinary conditions, H₂ doesn't react with Cu. But CuO can be reduced: $\text{CuO} + H_2 \to \text{Cu} + \text{H}_2\text{O}$. Cu alone has no reaction with H₂.
Final Answer: No reaction with Cu metal; only with CuO.
Write balanced equation for reaction of Zn with NaOH.
Show solution
$\text{Zn} + 2\text{NaOH} \to \text{Na}_2\text{ZnO}_2 + H_2$
Final Answer: Sodium zincate + H₂ liberated.
Lab preparation of H₂ uses:
Industrial H₂ production via:
H₂ + Cl₂ in sunlight gives:
H₂ reduces:
Atomic H torch produces temperature:
Compounds of Hydrogen
HydridesTopic 1
Hydrides: Binary compounds of hydrogen with other elements. Classified by bonding character.
Three Major Types:
| Type | Bonding | Examples | Properties |
|---|---|---|---|
| Ionic (Saline) Hydrides | Ionic; H is H⁻ | LiH, NaH, CaH₂, MgH₂ | Crystalline; high MP; conduct electricity in molten state; strongly reducing |
| Covalent (Molecular) Hydrides | Covalent; H shares e⁻ | CH₄, NH₃, H₂O, HF, HCl, B₂H₆ | Low MP, BP; mostly gases or volatile liquids; can be H-bonded |
| Metallic (Interstitial) Hydrides | H atoms in metallic lattice | Pd, Ti, La, Ce, Th hydrides | Variable composition; metallic luster; conduct electricity |
Ionic Hydrides:
- Formed by most reactive metals (Group 1 and heavier Group 2)
- Electrolysis liberates H₂ at anode (proves H⁻)
- React violently with water: $\text{NaH} + \text{H}_2\text{O} \to \text{NaOH} + H_2$
Covalent Hydrides are further classified:
| Sub-type | Example | Note |
|---|---|---|
| Electron-deficient | $B_2H_6, BH_3$ | Fewer e⁻ than required for normal Lewis structure; have 3-center-2-electron bonds |
| Electron-precise | $CH_4, SiH_4$ | Exact e⁻ for octets |
| Electron-rich | $NH_3, H_2O, HF$ | Lone pairs available; H-bonding possible |
Metallic Hydrides:
- Found in d- and f-block metals
- H₂ adsorbed in interstitial spaces of metal lattice
- Composition often non-stoichiometric (e.g., $TiH_{1.7}$)
- Used in H₂ storage technology
Some metals do NOT form stable hydrides:
- 7-11 groups of d-block (called "hydride gap": Cr, Mn, Fe, Co, Ni, Cu, Zn, etc.)
- This is where d-block has incomplete d-orbital filling/cohesion issues
Properties Comparison of Group 16 Hydrides:
| Property | H₂O | H₂S | H₂Se | H₂Te |
|---|---|---|---|---|
| BP | $100°$C | $-60°$C | $-41°$C | $-2°$C |
| Acidic strength | weakest | weak | moderate | strongest |
| Reducing power | weakest | weak | moderate | strongest |
H₂O has anomalously high BP due to H-bonding.
Why is LiH ionic but BeH₂ covalent?
Show solution
Li⁺ has low charge (+1) and reasonably large size → low polarizing power. So LiH is largely ionic. Be²⁺ has higher charge (+2) and smaller size → high polarizing power. By Fajan's rules, BeH₂ is more covalent.
Final Answer: Polarizing power of cation (Li⁺ low, Be²⁺ high) determines ionic vs covalent character.
Predict products: $CaH_2 + 2H_2O \to ?$
Show solution
$CaH_2 + 2H_2O \to Ca(OH)_2 + 2H_2 \uparrow$
CaH₂ acts as reducing agent; H⁻ + H⁺ → H₂.
Final Answer: $Ca(OH)_2$ + $2H_2$.
NaH is:
Hydride gap is observed for:
Most acidic among H₂O, H₂S, H₂Se, H₂Te:
$B_2H_6$ is:
When NaH dissolves in water:
Water, Hydrogen Peroxide and Water HardnessTopic 2
Water (H₂O): Universal solvent. High BP due to H-bonding. Max density at $4°$C (unique).
Properties:
- Amphoteric (acts as acid and base): $H_2O + HCl \to H_3O^+ + Cl^-$; $H_2O + NH_3 \to NH_4^+ + OH^-$
- Auto-ionization: $2H_2O \rightleftharpoons H_3O^+ + OH^-$, $K_w = 10^{-14}$ at $25°$C
- Hydration of ions (high dielectric constant ≈ $80$)
- Strong reducing properties in some reactions
Hardness of Water: Inability of water to form lather with soap. Caused by dissolved Ca²⁺ and Mg²⁺ ions (also Fe²⁺, sometimes).
Types:
| Hardness type | Cause | Removal |
|---|---|---|
| Temporary | Bicarbonates: $Ca(HCO_3)_2, Mg(HCO_3)_2$ | Boiling: $Ca(HCO_3)_2 \to CaCO_3\downarrow + H_2O + CO_2$; or Clark's process (add lime) |
| Permanent | Sulfates and chlorides: $CaCl_2, CaSO_4, MgSO_4$ | Sodium carbonate (washing soda), ion-exchange resins, Calgon, permutit, zeolite |
Clark's process (for temporary hardness): $Ca(HCO_3)_2 + Ca(OH)_2 \to 2CaCO_3\downarrow + 2H_2O$
Ion exchange (permutit): $Na_2P + Ca^{2+} \to CaP + 2Na^+$. Regenerated with NaCl solution.
Calgon process: Sodium hexametaphosphate $Na_6P_6O_{18}$ binds Ca²⁺ and Mg²⁺.
Soap action with hard water: $2C_{17}H_{35}COONa + CaSO_4 \to (C_{17}H_{35}COO)_2Ca\downarrow + Na_2SO_4$ (scum)
Units of Hardness: ppm (mg CaCO₃ per L) or degrees Clark.
Hydrogen Peroxide (H₂O₂):
Preparation:
- $BaO_2 + H_2SO_4 \to BaSO_4 + H_2O_2$
- $2NH_4HSO_4 \xrightarrow{\text{electrolysis}} (NH_4)_2S_2O_8 \xrightarrow{H_2O} 2NH_4HSO_4 + H_2O_2$
- Auto-oxidation of 2-ethyl anthraquinol (industrial)
Structure: Non-planar; "open book" structure. O-O bond is single ($\sim$ $1.49$ Å). H-O-O-H dihedral angle $\sim 111°$ in gas, $\sim 90°$ in solid.
Properties:
- Colorless, viscous liquid (sometimes pale blue in pure form)
- Miscible with water
- Unstable; decomposes to $H_2O + O_2$ (catalyzed by MnO₂, Pt, light)
Concentration Expressions:
- % by mass (e.g., 30%)
- Volume strength: Volume of O₂ released at STP per volume of H₂O₂ solution. "$20$ V" means 1 L of H₂O₂ releases 20 L O₂.
- $\text{Volume strength} = 5.6 \times N$
- $\text{Volume strength} = 11.2 \times M$
Chemical Properties:
- As oxidizing agent: $H_2O_2 + 2I^- + 2H^+ \to I_2 + 2H_2O$
- As reducing agent: $H_2O_2 + Cl_2 \to 2HCl + O_2$; also reduces KMnO₄ in acidic medium
- Acidic nature: Weak diprotic acid; $K_{a1} = 1.6 \times 10^{-12}$
- Disproportionation: $2H_2O_2 \to 2H_2O + O_2$
Uses:
- Antiseptic (3% in dental rinses)
- Bleaching agent (paper, hair, textiles)
- Rocket propellant ($90\%$)
- Synthesis of organic compounds (epoxidation, hydroxylation)
- Pollution control (removes H₂S)
Differentiate between temporary and permanent hardness and methods to remove.
Show solution
Temporary: Due to $Ca(HCO_3)_2$, $Mg(HCO_3)_2$. Removed by boiling (decomposes to CaCO₃ ppt) or Clark's process. Permanent: Due to chlorides and sulfates of Ca²⁺, Mg²⁺. Removed by washing soda, ion exchange, Calgon, zeolite.
Final Answer: Differ in source (bicarbonates vs sulfates/chlorides) and removal methods.
Calculate molarity of "$20$ V" H₂O₂.
Show solution
Volume strength $= 11.2 \times M \implies M = 20/11.2 = 1.786$ M.
Final Answer: $M \approx 1.79$ M.
Hard water does not lather well due to:
Temporary hardness is removed by:
Calgon is:
Volume strength "$10$ V" of H₂O₂ in mass percent (approx):
$H_2O_2$ in acidic medium acts as:
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