JEE Main & Advanced

Hydrogen

Hydrogen for JEE Main & Advanced

1
Module 1

Hydrogen — Position, Isotopes, Preparation

Position in Periodic Table and IsotopesTopic 1

Hydrogen ($Z = 1$, configuration $1s^1$) is unique — it shows similarities with both alkali metals (Group 1) and halogens (Group 17). Its position in the periodic table is debated.

Resemblance with Alkali Metals:

  • Electronic configuration: $ns^1$
  • Forms unipositive ion (H⁺)
  • Forms halides (HCl like NaCl)
  • Reducing nature

Resemblance with Halogens:

  • One electron short of noble gas configuration
  • Forms diatomic molecule (H₂)
  • Forms uninegative ion (H⁻, hydride)
  • Combines with metals and non-metals

Unique Features:

  • Smallest atom
  • H⁺ is just a bare proton (no electrons) — different from any other cation
  • Lower IE than expected for halogens
  • Higher IE than alkali metals

Isotopes of Hydrogen:

IsotopeSymbolCompositionAbundanceProperties
Protium$^1H$ or H$1p, 1e, 0n$$99.98\%$Common hydrogen
Deuterium$^2H$ or D$1p, 1e, 1n$$0.015\%$Heavy hydrogen
Tritium$^3H$ or T$1p, 1e, 2n$Trace ($10^{-15}\%$)Radioactive ($\beta^-$ emitter, $t_{1/2} = 12.3$ years)

Heavy Water (D₂O): $D_2O$ (deuterium oxide). Properties differ slightly from $H_2O$:

  • Higher BP ($101.4°$C vs $100°$C)
  • Higher MP ($3.8°$C vs $0°$C)
  • Higher density ($1.106$ g/mL vs $1.000$)
  • Used as moderator in nuclear reactors (slows neutrons without absorbing them)
  • Toxic in large amounts to organisms

Ortho and Para Hydrogen:

  • Ortho: nuclear spins parallel (75% at room T)
  • Para: nuclear spins antiparallel (25% at room T)
  • At low T (below 20 K), all converts to para (more stable)
Worked Examples
1

Compare hydrogen with alkali metals and halogens.

Show solution

Similarities with alkali metals: $ns^1$ config, forms M⁺, reducing. Similarities with halogens: forms H⁻, diatomic H₂, one e⁻ short of noble gas. Differences: H is non-metal, gas at RT; alkali metals are solid metals. H is not as electronegative as halogens. Therefore, H is uniquely placed — neither pure alkali nor pure halogen.

Final Answer: H shows dual character but matches neither group fully.

2

Why is D₂O used as a moderator in nuclear reactors?

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$D_2O$ slows down fast neutrons (released in fission) by elastic collision. Since D has similar mass to neutron, it effectively slows neutrons. Unlike H, D does not absorb neutrons much — keeping neutron flux available for further fission.

Final Answer: Moderates (slows) neutrons without absorbing them.

✎ Self-Check — 5 questions0 / 5
Q1.

Hydrogen resembles alkali metals due to:

Q2.

Tritium is:

Q3.

Mass number of deuterium:

Q4.

Heavy water is used in:

Q5.

Ortho-hydrogen at room temperature has fraction:

Preparation and Properties of HydrogenTopic 2

Laboratory Preparation:

  • Action of dilute HCl or H₂SO₄ on Zn:

$$\text{Zn} + 2\text{HCl} \to \text{ZnCl}_2 + \text{H}_2$$ $$\text{Zn} + \text{H}_2\text{SO}_4 \to \text{ZnSO}_4 + \text{H}_2$$

  • (Pure H₂): Action of NaOH on Al or Zn:

$$2\text{Al} + 6\text{NaOH} \to 2\text{Na}_3\text{AlO}_3 + 3\text{H}_2$$

  • Action of pure water on Na (violent — not preferred):

$$2\text{Na} + 2\text{H}_2\text{O} \to 2\text{NaOH} + \text{H}_2$$

Industrial Preparation:

MethodReactionNotes
Bosch process$C + H_2O \to CO + H_2$ (water gas); then $CO + H_2O \to CO_2 + H_2$ on Fe catalystHigh T
Lane process$3\text{Fe} + 4\text{H}_2\text{O} \to \text{Fe}_3\text{O}_4 + 4\text{H}_2$ (alternate steam pass)$1000$ K
From hydrocarbons (steam reforming)$\text{CH}_4 + \text{H}_2\text{O} \to \text{CO} + 3\text{H}_2$Ni catalyst, $1100$ K
Electrolysis of water$2\text{H}_2\text{O} \to 2\text{H}_2 + \text{O}_2$Trace acid/base added

Physical Properties:

  • Colorless, odorless, tasteless, non-toxic gas
  • Lightest gas (M = 2)
  • BP $-253°$C, MP $-259°$C
  • Slightly soluble in water; very soluble in metals like Pd (used for purification)

Chemical Properties:

  1. Combustion: $2H_2 + O_2 \to 2H_2O + \text{heat}$ (used in rockets; produces water vapor only — clean fuel)
  2. With halogens: $H_2 + X_2 \to 2HX$. Reactivity: F > Cl > Br > I.
  3. With nitrogen (Haber): $N_2 + 3H_2 \rightleftharpoons 2NH_3$ (high P, T, Fe catalyst)
  4. With metals (hydrides): $2\text{Na} + H_2 \to 2\text{NaH}$
  5. Reducing agent: Reduces metal oxides ($\text{CuO} + H_2 \to \text{Cu} + \text{H}_2\text{O}$)
  6. Hydrogenation: Catalytic addition to unsaturated C=C and C=O (Ni, Pd, Pt catalysts)

Uses of Hydrogen:

  • Hydrogenation of oils → vanaspati ghee
  • Ammonia synthesis (Haber)
  • Production of methanol ($\text{CO} + 2H_2 \to \text{CH}_3\text{OH}$)
  • Rocket fuel (with O₂)
  • Atomic hydrogen torch (welding metals; very high temperature)
  • Hydrogen as fuel (zero emissions; fuel cell)
Worked Examples
1

Predict product: $\text{Cu(s)} + H_2 \xrightarrow{\Delta} ?$

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At ordinary conditions, H₂ doesn't react with Cu. But CuO can be reduced: $\text{CuO} + H_2 \to \text{Cu} + \text{H}_2\text{O}$. Cu alone has no reaction with H₂.

Final Answer: No reaction with Cu metal; only with CuO.

2

Write balanced equation for reaction of Zn with NaOH.

Show solution

$\text{Zn} + 2\text{NaOH} \to \text{Na}_2\text{ZnO}_2 + H_2$

Final Answer: Sodium zincate + H₂ liberated.

✎ Self-Check — 5 questions0 / 5
Q1.

Lab preparation of H₂ uses:

Q2.

Industrial H₂ production via:

Q3.

H₂ + Cl₂ in sunlight gives:

Q4.

H₂ reduces:

Q5.

Atomic H torch produces temperature:

2
Module 2

Compounds of Hydrogen

HydridesTopic 1

Hydrides: Binary compounds of hydrogen with other elements. Classified by bonding character.

Three Major Types:

TypeBondingExamplesProperties
Ionic (Saline) HydridesIonic; H is H⁻LiH, NaH, CaH₂, MgH₂Crystalline; high MP; conduct electricity in molten state; strongly reducing
Covalent (Molecular) HydridesCovalent; H shares e⁻CH₄, NH₃, H₂O, HF, HCl, B₂H₆Low MP, BP; mostly gases or volatile liquids; can be H-bonded
Metallic (Interstitial) HydridesH atoms in metallic latticePd, Ti, La, Ce, Th hydridesVariable composition; metallic luster; conduct electricity

Ionic Hydrides:

  • Formed by most reactive metals (Group 1 and heavier Group 2)
  • Electrolysis liberates H₂ at anode (proves H⁻)
  • React violently with water: $\text{NaH} + \text{H}_2\text{O} \to \text{NaOH} + H_2$

Covalent Hydrides are further classified:

Sub-typeExampleNote
Electron-deficient$B_2H_6, BH_3$Fewer e⁻ than required for normal Lewis structure; have 3-center-2-electron bonds
Electron-precise$CH_4, SiH_4$Exact e⁻ for octets
Electron-rich$NH_3, H_2O, HF$Lone pairs available; H-bonding possible

Metallic Hydrides:

  • Found in d- and f-block metals
  • H₂ adsorbed in interstitial spaces of metal lattice
  • Composition often non-stoichiometric (e.g., $TiH_{1.7}$)
  • Used in H₂ storage technology

Some metals do NOT form stable hydrides:

  • 7-11 groups of d-block (called "hydride gap": Cr, Mn, Fe, Co, Ni, Cu, Zn, etc.)
  • This is where d-block has incomplete d-orbital filling/cohesion issues

Properties Comparison of Group 16 Hydrides:

PropertyH₂OH₂SH₂SeH₂Te
BP$100°$C$-60°$C$-41°$C$-2°$C
Acidic strengthweakestweakmoderatestrongest
Reducing powerweakestweakmoderatestrongest

H₂O has anomalously high BP due to H-bonding.

Worked Examples
1

Why is LiH ionic but BeH₂ covalent?

Show solution

Li⁺ has low charge (+1) and reasonably large size → low polarizing power. So LiH is largely ionic. Be²⁺ has higher charge (+2) and smaller size → high polarizing power. By Fajan's rules, BeH₂ is more covalent.

Final Answer: Polarizing power of cation (Li⁺ low, Be²⁺ high) determines ionic vs covalent character.

2

Predict products: $CaH_2 + 2H_2O \to ?$

Show solution

$CaH_2 + 2H_2O \to Ca(OH)_2 + 2H_2 \uparrow$

CaH₂ acts as reducing agent; H⁻ + H⁺ → H₂.

Final Answer: $Ca(OH)_2$ + $2H_2$.

✎ Self-Check — 5 questions0 / 5
Q1.

NaH is:

Q2.

Hydride gap is observed for:

Q3.

Most acidic among H₂O, H₂S, H₂Se, H₂Te:

Q4.

$B_2H_6$ is:

Q5.

When NaH dissolves in water:

Water, Hydrogen Peroxide and Water HardnessTopic 2

Water (H₂O): Universal solvent. High BP due to H-bonding. Max density at $4°$C (unique).

Properties:

  • Amphoteric (acts as acid and base): $H_2O + HCl \to H_3O^+ + Cl^-$; $H_2O + NH_3 \to NH_4^+ + OH^-$
  • Auto-ionization: $2H_2O \rightleftharpoons H_3O^+ + OH^-$, $K_w = 10^{-14}$ at $25°$C
  • Hydration of ions (high dielectric constant ≈ $80$)
  • Strong reducing properties in some reactions

Hardness of Water: Inability of water to form lather with soap. Caused by dissolved Ca²⁺ and Mg²⁺ ions (also Fe²⁺, sometimes).

Types:

Hardness typeCauseRemoval
TemporaryBicarbonates: $Ca(HCO_3)_2, Mg(HCO_3)_2$Boiling: $Ca(HCO_3)_2 \to CaCO_3\downarrow + H_2O + CO_2$; or Clark's process (add lime)
PermanentSulfates and chlorides: $CaCl_2, CaSO_4, MgSO_4$Sodium carbonate (washing soda), ion-exchange resins, Calgon, permutit, zeolite

Clark's process (for temporary hardness): $Ca(HCO_3)_2 + Ca(OH)_2 \to 2CaCO_3\downarrow + 2H_2O$

Ion exchange (permutit): $Na_2P + Ca^{2+} \to CaP + 2Na^+$. Regenerated with NaCl solution.

Calgon process: Sodium hexametaphosphate $Na_6P_6O_{18}$ binds Ca²⁺ and Mg²⁺.

Soap action with hard water: $2C_{17}H_{35}COONa + CaSO_4 \to (C_{17}H_{35}COO)_2Ca\downarrow + Na_2SO_4$ (scum)

Units of Hardness: ppm (mg CaCO₃ per L) or degrees Clark.

Hydrogen Peroxide (H₂O₂):

Preparation:

  • $BaO_2 + H_2SO_4 \to BaSO_4 + H_2O_2$
  • $2NH_4HSO_4 \xrightarrow{\text{electrolysis}} (NH_4)_2S_2O_8 \xrightarrow{H_2O} 2NH_4HSO_4 + H_2O_2$
  • Auto-oxidation of 2-ethyl anthraquinol (industrial)

Structure: Non-planar; "open book" structure. O-O bond is single ($\sim$ $1.49$ Å). H-O-O-H dihedral angle $\sim 111°$ in gas, $\sim 90°$ in solid.

Properties:

  • Colorless, viscous liquid (sometimes pale blue in pure form)
  • Miscible with water
  • Unstable; decomposes to $H_2O + O_2$ (catalyzed by MnO₂, Pt, light)

Concentration Expressions:

  • % by mass (e.g., 30%)
  • Volume strength: Volume of O₂ released at STP per volume of H₂O₂ solution. "$20$ V" means 1 L of H₂O₂ releases 20 L O₂.
  • $\text{Volume strength} = 5.6 \times N$
  • $\text{Volume strength} = 11.2 \times M$

Chemical Properties:

  1. As oxidizing agent: $H_2O_2 + 2I^- + 2H^+ \to I_2 + 2H_2O$
  2. As reducing agent: $H_2O_2 + Cl_2 \to 2HCl + O_2$; also reduces KMnO₄ in acidic medium
  3. Acidic nature: Weak diprotic acid; $K_{a1} = 1.6 \times 10^{-12}$
  4. Disproportionation: $2H_2O_2 \to 2H_2O + O_2$

Uses:

  • Antiseptic (3% in dental rinses)
  • Bleaching agent (paper, hair, textiles)
  • Rocket propellant ($90\%$)
  • Synthesis of organic compounds (epoxidation, hydroxylation)
  • Pollution control (removes H₂S)
Worked Examples
1

Differentiate between temporary and permanent hardness and methods to remove.

Show solution

Temporary: Due to $Ca(HCO_3)_2$, $Mg(HCO_3)_2$. Removed by boiling (decomposes to CaCO₃ ppt) or Clark's process. Permanent: Due to chlorides and sulfates of Ca²⁺, Mg²⁺. Removed by washing soda, ion exchange, Calgon, zeolite.

Final Answer: Differ in source (bicarbonates vs sulfates/chlorides) and removal methods.

2

Calculate molarity of "$20$ V" H₂O₂.

Show solution

Volume strength $= 11.2 \times M \implies M = 20/11.2 = 1.786$ M.

Final Answer: $M \approx 1.79$ M.

✎ Self-Check — 5 questions0 / 5
Q1.

Hard water does not lather well due to:

Q2.

Temporary hardness is removed by:

Q3.

Calgon is:

Q4.

Volume strength "$10$ V" of H₂O₂ in mass percent (approx):

Q5.

$H_2O_2$ in acidic medium acts as:

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