JEE Main & Advanced

Organic Chemistry

Organic Chemistry for JEE Main & Advanced

1
Module 1

Nomenclature, Isomerism and Electron Effects

IUPAC Nomenclature and IsomerismTopic 1

IUPAC Naming Rules:

  1. Identify longest C chain containing the principal functional group (parent)
  2. Number from end giving lowest locant to principal functional group
  3. Identify substituents (prefixes) — alphabetize
  4. Combine: locants–prefixes–parent–suffix
  5. Use Greek prefixes (di, tri) for multiple substituents — these don't affect alphabetization

Common Functional Groups (in order of priority for suffix):

GroupClassSuffixPrefix
-COOHCarboxylic acid-oic acidcarboxy-
-COO-REster-oatealkoxycarbonyl-
-CONH₂Amide-amidecarbamoyl-
-CNNitrile-nitrilecyano-
-CHOAldehyde-alformyl-/oxo-
-CO-Ketone-oneoxo-
-OHAlcohol-olhydroxy-
-NH₂Amine-amineamino-
C=CAlkene-ene
C≡CAlkyne-yne
-XHalidehalo-
-NO₂Nitronitro-
-OREtheralkoxy-

Examples:

  • $CH_3CH_2CH_2OH$ → propan-1-ol
  • $(CH_3)_2CHCH_2CH_3$ → 2-methylbutane
  • $CH_3COOH$ → ethanoic acid
  • $CH_3CH=CH_2$ → propene

Isomerism: Compounds with same molecular formula but different structure/properties.

Types of Isomerism:

Structural (Constitutional) Isomerism:

TypeDescriptionExample
ChainDifferent C skeletonn-butane vs isobutane (both $C_4H_{10}$)
PositionSame skeleton, different position of group/bond1-propanol vs 2-propanol
FunctionalDifferent functional groups$C_2H_6O$: ethanol (alcohol) vs dimethyl ether
MetamerismDifferent alkyl groups on same functional groupDiethyl ether vs methyl propyl ether
TautomerismEquilibrium between two forms differing in H positionKeto-enol: $CH_3COCH_3 \rightleftharpoons CH_3C(OH)=CH_2$
Ring-chainCyclic vs open-chainCyclopropane vs propene

Stereoisomerism: Same connectivity; differ in 3D arrangement.

Geometrical (cis-trans / E-Z): Around C=C or ring restricted rotation.

  • cis: same group on same side
  • trans: groups on opposite sides
  • E/Z system: Based on CIP priority — Z (zusammen, same side) and E (entgegen, opposite)

Optical Isomerism: Mirror image molecules (enantiomers) that are non-superimposable. Requires chiral center — usually a C with 4 different groups.

  • Enantiomers: Non-superimposable mirror images; identical properties except rotate polarized light in opposite directions (one (+), other (–))
  • Diastereomers: Stereoisomers not mirror images; different properties
  • Racemic mixture: $50:50$ of enantiomers; no optical activity (rotations cancel)
  • Meso compound: Has chiral centers but is superimposable on mirror image due to internal symmetry; optically inactive

For $n$ chiral centers without symmetry: $2^n$ optical isomers; with internal symmetry, fewer.

R/S Configuration (CIP): Assign priority by atomic number; for the lowest-priority pointing away: clockwise = R, counterclockwise = S.

Worked Examples
1

Give IUPAC name: $CH_3-CH(CH_3)-CH_2-CHO$.

Show solution
  • Parent: longest chain containing -CHO = 4 C atoms
  • Suffix: -al; -CHO is C1
  • Substituent: methyl at C3
  • Name: 3-methylbutanal

Final Answer: 3-methylbutanal.

2

How many stereoisomers does 2,3-dibromobutane ($CH_3CHBrCHBrCH_3$) have?

Show solution

2 chiral centers (C2 and C3, each bonded to 4 different groups: H, Br, $CH_3$, $CHBrCH_3$). But this molecule has a plane of symmetry → meso compound exists. Total: 4 expected ($2^2$); but $(R,S)$ and $(S,R)$ are identical (meso). Effective stereoisomers: $(R,R)$, $(S,S)$ (enantiomers) + 1 meso = 3 distinct stereoisomers.

Final Answer: 3 stereoisomers (1 pair enantiomers + 1 meso).

✎ Self-Check — 5 questions0 / 5
Q1.

IUPAC name of $(CH_3)_3CCl$:

Q2.

Tautomerism is shown by:

Q3.

Compound with chiral center:

Q4.

Cis-trans isomerism occurs when:

Q5.

Number of structural isomers of $C_4H_{10}$:

Electron Displacement Effects (I, R, Hyperconjugation)Topic 2

Electron displacement effects explain charge distribution in molecules, stability of intermediates, acidity/basicity, reactivity, etc.

1. Inductive Effect (I-Effect):

  • Permanent displacement of electrons along $\sigma$ bonds due to electronegativity difference
  • Transmitted through sigma bonds with diminishing intensity
  • Distance-dependent: decreases rapidly beyond 3 bonds

Types:

  • -I (electron-withdrawing): Group pulls electrons toward itself. e.g., $-NO_2 > -CN > -F > -Cl > -Br > -I > -COOH > -OH > -NH_2$
  • +I (electron-donating): Group pushes electrons away. e.g., alkyl groups: $-CH_3, -C_2H_5$, etc. Order: $tert > sec > primary > methyl$ (more substituted → more +I).

Applications:

  • Acidity of carboxylic acids:
  • Cl₃C-COOH > Cl₂CH-COOH > ClCH₂-COOH > CH₃COOH (more -I → more acidic)
  • Basicity of amines (gas phase): $(CH_3)_3N > (CH_3)_2NH > CH_3NH_2 > NH_3$ (more +I → more basic)

2. Resonance Effect (M-Effect or R-Effect):

  • Permanent delocalization of $\pi$ electrons or lone pairs
  • Only operates through conjugated $\pi$ system
  • More effective than I-effect

Types:

  • +R (electron-donating to ring): $-OH, -OR, -NH_2, -NR_2, -X$ (donate lone pairs)
  • -R (electron-withdrawing from ring): $-NO_2, -CN, -CHO, -COOH, -COR, -SO_3H$

Resonance Structures: Different Lewis structures contributing to actual structure; differ in placement of electrons (not atoms).

3. Hyperconjugation:

  • Delocalization of $\sigma$ C-H electrons into adjacent $\pi$ system or empty p-orbital
  • Also called "no-bond resonance"

Stability of carbocations $\propto$ number of $\alpha$-H atoms (more $\alpha$-H → more hyperconjugation → more stable):

  • $(CH_3)_3C^+$ (9 α-H) > $(CH_3)_2CH^+$ (6 α-H) > $CH_3CH_2^+$ (3 α-H) > $CH_3^+$ (0 α-H)

Stability of alkenes: More alkyl substituents at C=C → more stable (hyperconjugation): $$(CH_3)_2C=C(CH_3)_2 > (CH_3)_2C=CH_2 > CH_3CH=CHCH_3 > CH_3CH=CH_2 > CH_2=CH_2$$

4. Electromeric Effect (E-effect):

  • Temporary; only when an attacking reagent approaches
  • $\pi$ electrons transferred entirely to one atom
  • +E: electrons toward attacking reagent; -E: electrons away
Worked Examples
1

Arrange in increasing acidity: $CH_3COOH$, $HCOOH$, $Cl_3CCOOH$, $ClCH_2COOH$.

Show solution

Acidity depends on stability of conjugate base; more EW (-I) groups stabilize the COO⁻ more, increasing acidity.

  • $CH_3COOH$: +I from methyl → less acidic
  • $HCOOH$: no alkyl, no -I
  • $ClCH_2COOH$: 1 Cl (-I)
  • $Cl_3CCOOH$: 3 Cl (highest -I)

Order: $CH_3COOH < HCOOH < ClCH_2COOH < Cl_3CCOOH$.

Final Answer: $CH_3COOH < HCOOH < ClCH_2COOH < Cl_3CCOOH$.

2

Why is $(CH_3)_3C^+$ more stable than $CH_3CH_2^+$?

Show solution

$(CH_3)_3C^+$ has 9 α-H atoms; $CH_3CH_2^+$ has 3 α-H atoms. More α-H → more hyperconjugation → more delocalization → greater stability. Also, more +I effect from alkyl groups stabilizes positive charge.

Final Answer: More α-H + more +I in $(CH_3)_3C^+$ → more stable.

✎ Self-Check — 5 questions0 / 5
Q1.

Inductive effect operates through:

Q2.

Strongest -I group:

Q3.

Hyperconjugation involves:

Q4.

Most stable carbocation:

Q5.

Resonance effect operates only through:

2
Module 2

Reactive Intermediates and Mechanisms

Carbocations, Carbanions, Free Radicals, CarbenesTopic 1

Reactive Intermediates are short-lived, high-energy species formed during reactions.

1. Carbocations (Carbenium ions):

  • C with $+$ charge, 6 valence electrons (sextet)
  • $sp^2$ hybridized, planar, vacant p-orbital
  • Electrophilic

Stability Order: $(CH_3)_3C^+ > (CH_3)_2CH^+ > CH_3CH_2^+ > CH_3^+$ (more $\alpha$-H → more hyperconjugation, more +I from alkyl)

Allylic and Benzylic carbocations are stabilized by resonance, often more stable than tertiary: $(C_6H_5)CH_2^+ \approx CH_2=CHCH_2^+ \approx$ very stable

Tertiary > secondary > primary > methyl is the basic order; resonance can override this.

Rearrangement: Carbocations can rearrange to more stable forms via:

  • 1,2-Hydride shift
  • 1,2-Methyl shift (or other alkyl shift)

2. Carbanions:

  • C with $-$ charge, 8 valence electrons (lone pair on C)
  • $sp^3$ hybridized, pyramidal (like NH₃)
  • Nucleophilic

Stability Order: $CH_3^- > CH_3CH_2^- > (CH_3)_2CH^- > (CH_3)_3C^-$ (alkyl groups destabilize negative charge via +I)

Stabilized carbanions (by -R groups via resonance):

  • Benzylic: $C_6H_5CH_2^-$ (more stable than methyl due to resonance)
  • Allylic: $CH_2=CHCH_2^-$
  • Especially: $\alpha$-carbon of carbonyl (enolate ions), nitro compounds

Hybridization Effect: More s-character → more stable carbanion. So: $sp$ (alkyne, acetylide $RC\equiv C^-$) > $sp^2$ > $sp^3$.

3. Free Radicals:

  • C with 7 valence electrons (unpaired electron)
  • $sp^2$ hybridized, planar (some texts say pyramidal)
  • Neutral; very reactive

Stability Order: Similar to carbocations: $3° > 2° > 1° > methyl$

  • Allylic, benzylic > 3° > 2° > 1° > methyl (resonance stabilization)

Generation: Photolysis ($h\nu$), peroxides ($RO-OR \to 2RO\cdot$), thermal, halogenation.

Detection: EPR (electron paramagnetic resonance).

4. Carbenes:

  • C with 6 valence electrons; two non-bonding electrons
  • Singlet carbene: paired electrons in one orbital
  • Triplet carbene: two unpaired electrons (more stable for simple carbene)

Generation: $CHCl_3 + KOH \to :CCl_2 + KCl + H_2O$ (dichlorocarbene) Reaction: Insert into C-H bonds; add to C=C (cyclopropanation).

5. Nitrenes:

  • N analog of carbenes (sextet on N)
Worked Examples
1

Predict major product after rearrangement: $(CH_3)_2CHCH_2^+$.

Show solution

$(CH_3)_2CHCH_2^+$ is a primary carbocation. It can undergo 1,2-H shift to form a tertiary carbocation: $(CH_3)_2CHCH_2^+ \to (CH_3)_2C^+CH_3$ (more stable, tertiary).

Final Answer: Tertiary carbocation $(CH_3)_3C^+$ via hydride shift.

2

Arrange in increasing stability of free radicals: methyl, ethyl, isopropyl, t-butyl, benzyl.

Show solution

Pattern follows carbocation order due to hyperconjugation/resonance: methyl < ethyl < isopropyl < t-butyl < benzyl (benzyl most stable due to resonance with ring).

Final Answer: methyl < ethyl < isopropyl < t-butyl < benzyl.

✎ Self-Check — 5 questions0 / 5
Q1.

Carbocation is:

Q2.

Most stable carbocation:

Q3.

Carbanion has:

Q4.

Allylic free radical is stabilized by:

Q5.

Dichlorocarbene is formed from CHCl₃ by:

Electrophiles, Nucleophiles, Reaction Types and PurificationTopic 2

Electrophiles (E⁺): Electron-poor; "electron lovers". Accept electron pair. Examples: $H^+, NO_2^+, Cl^+, Br^+, R^+, AlCl_3$ (Lewis acid), $SO_3$, carbonyl C.

Nucleophiles (Nu⁻): Electron-rich; "nucleus lovers". Donate electron pair.

  • Negatively charged: $OH^-, CN^-, Cl^-, RO^-, RS^-, NH_2^-$
  • Neutral with lone pair: $H_2O, NH_3, ROH$
  • Strong nucleophiles: $OH^-, RO^-, RS^-, NH_2^-, CN^-, RC \equiv C^-$
  • Weak nucleophiles: $H_2O, ROH, Cl^-, HSO_4^-$

Reaction Types in Organic Chemistry:

TypeDescriptionExample
SubstitutionAtom/group replaced by another$CH_3Cl + OH^- \to CH_3OH + Cl^-$
AdditionTwo species combine; unsaturated bond saturates$CH_2=CH_2 + H_2 \to CH_3CH_3$
EliminationLost groups → unsaturated product$CH_3CH_2Br + OH^- \to CH_2=CH_2$
RearrangementGroup migration within moleculeCarbocation rearrangements

Subdivisions:

  • Nucleophilic (N): nucleophile attacks; in saturated C: $S_N1$, $S_N2$; in unsaturated C (carbonyl): $A_N$
  • Electrophilic (E): electrophile attacks; in aromatic: $S_E$ (also called $E_{Ar}$); in alkenes: $A_E$
  • Radical (R): radicals involved; $S_R$, $A_R$

Common Reaction Patterns:

  • Free radical substitution: alkane + halogen (light)
  • Electrophilic addition: alkene + HX, X₂, H₂O (acid), etc.
  • Electrophilic aromatic substitution: benzene + Friedel-Crafts, nitration, halogenation, etc.
  • Nucleophilic substitution: RX + Nu⁻
  • Nucleophilic addition: R₂C=O + Nu⁻ → R₂C(OH)(Nu)
  • Nucleophilic acyl substitution: RCOOR' + Nu⁻ → RCONu + R'O⁻

Methods of Purification:

MethodPrincipleUsed For
FiltrationSolid-liquid separationInsoluble solids in liquid
CrystallizationDifferent solubilities at different TSolids; purified by recrystallization
DistillationDifferent BPsVolatile liquids of significantly different BPs
Fractional distillationSlight BP differencesMixtures with close BPs (petroleum)
Steam distillationSubstance volatile, insoluble in waterHeat-sensitive, water-immiscible compounds (aniline, essential oils)
Vacuum distillationReduced P to lower BPHeat-sensitive compounds (glycerol)
SublimationSolid → vapor directlySolids that sublime (camphor, NH₄Cl, I₂, naphthalene)
ChromatographyDifferential adsorption/partitionMixtures of various sizes
Solvent extractionDifferent solubility in two immiscible solventsLiquid-liquid separation
Differential extractionSame as above with multiple stepsImproving yield

Chromatography Types:

  • Adsorption: TLC (Thin Layer), Column
  • Partition: Paper, HPLC (High Performance)
  • Gas chromatography (GC): Gaseous sample
  • GLC, GSC
Worked Examples
1

Classify: $H_2O + CH_3Cl \to CH_3OH + HCl$.

Show solution
  • $H_2O$ acts as nucleophile (lone pair on O)
  • $CH_3Cl$ is the substrate; Cl is leaving group
  • Substitution at $sp^3$ C → Nucleophilic Substitution ($S_N1$ or $S_N2$)

Final Answer: Nucleophilic substitution.

2

Which technique to purify glycerol (BP $290°$C, decomposes on heating)?

Show solution

Glycerol has high BP and decomposes at high T at atmospheric pressure. Use vacuum distillation (reduce P, lowers BP, avoids decomposition).

Final Answer: Vacuum distillation.

✎ Self-Check — 5 questions0 / 5
Q1.

Electrophile is:

Q2.

$OH^-$ acts as:

Q3.

Two liquids with similar BP separated by:

Q4.

To purify camphor:

Q5.

Type of reaction: $CH_2=CH_2 + HBr \to CH_3CH_2Br$:

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