Parabola
Parabola for JEE Main & Advanced
Introduction and General Conic
Focus-Directrix Definition and EccentricityTopic 1
A conic section is defined locus-wise as the path tracked by a variable coordinate point $P$ whose distance from a fixed point $S$ (the focus) bears a constant ratio $e$ (the eccentricity) to its perpendicular distance from a fixed straight line $L = 0$ (the directrix). \[ \frac{\text{Distance from Focus } (SP)}{\text{Distance from Directrix } (PM)} = e \implies SP = e \cdot PM. \]
\[ \begin{array}{ll} \textbf{Eccentricity Value } (e) & \textbf{Resulting Conic Profile} \\ e = 1 & \text{Parabola} \\ 0 < e < 1 & \text{Ellipse} \\ e > 1 & \text{Hyperbola} \\ e = 0 & \text{Circle} \\ \end{array} \]
Standard Parabola: $y^2 = 4ax$
Key ElementsTopic 1
\begin{formulabox}[Standard Form and Key Elements ($a > 0$)] \[ y^2 = 4ax \]
| Geometric Element | Value / Coordinate Form |
| Vertex | $(0,0)$ |
| Focus ($S$) | $(a,0)$ |
| Directrix Line ($L$) | $x = -a \implies x + a = 0$ |
| Axis of Symmetry | $y = 0$ (the horizontal $x$-axis) |
| Latus Rectum Line Chord | $x = a$; Total Length $= 4a$ |
| Ends of Latus Rectum ($L_1, L_2$) | $(a, 2a)$ and $(a, -2a)$ |
| Focal Distance of any Point $P(x_1,y_1)$ | $SP = x_1 + a$ |
Other Standard OrientationsTopic 2
| Equation | Opens | Vertex | Focus | Directrix | Axis Equation |
| $y^2 = 4ax\;(a>0)$ | Right | $(0,0)$ | $(a,0)$ | $x=-a$ | $y=0$ |
| $y^2 = -4ax$ | Left | $(0,0)$ | $(-a,0)$ | $x=a$ | $y=0$ |
| $x^2 = 4ay\;(a>0)$ | Upward | $(0,0)$ | $(0,a)$ | $y=-a$ | $x=0$ |
| $x^2 = -4ay$ | Downward | $(0,0)$ | $(0,-a)$ | $y=a$ | $x=0$ |
Shifted (Translated) ParabolaTopic 3
When the vertex of the parabola is translated away from the origin to a new coordinate point $(h, k)$, the standard equations shift linearly: \[ (y - k)^2 = 4a(x - h) \quad \text{or} \quad (x-h)^2 = 4a(y-k). \]
Parametric Form
Parametric Properties and Chord SlopesTopic 1
- [leftmargin=*]
- Focal Distance of Parameter $t$: The distance from the focus $S(a,0)$ to the parameter point $P(t)$ simplifies to: \[ |SP| = at^2 + a = a(1+t^2). \]
- Slope of a General Chord: The straight line connecting two distinct parameter points $P(t_1)$ and $Q(t_2)$ has its slope calculated as: \[ m = \frac{2at_2 - 2at_1}{at_2^2 - at_1^2} = \frac{2a(t_2 - t_1)}{a(t_2 - t_1)(t_2 + t_1)} = \frac{2}{t_1 + t_2} \quad (t_1 + t_2 \neq 0). \]
Equations of Tangent
Tangent at a Point $(x_1, y_1)$Topic 1
\begin{formulabox}[Point Form] \[ y y_1 = 2a(x + x_1) \] Derived using the standard $T = 0$ transform configuration matrix template: replace $y^2 \to y y_1$, and linear components $x \to \frac{x+x_1}{2}$. \end{formulabox}
Tangent in Parametric FormTopic 2
\begin{formulabox}[Parametric Form — at point $t$] \[ ty = x + at^2 \] \end{formulabox}
Tangent in Slope FormTopic 3
\begin{formulabox}[Slope Form — slope $m$] \[ y = mx + \frac{a}{m} \quad (m \neq 0) \] The matching precise point of tangency contact is given by: $\left(\dfrac{a}{m^2},\, \dfrac{2a}{m}\right)$. \end{formulabox}
\begin{importantbox}[Condition of Tangency] The straight line $y = mx + c$ is a valid tangent line to the standard parabola $y^2 = 4ax$ if and only if: \[ c = \frac{a}{m}. \] \end{importantbox}
Key Properties of TangentsTopic 4
- Tangents drawn at the endpoints of the latus rectum intersect at right angles on the directrix line.
- The point of intersection of two tangents drawn at parameters $t_1$ and $t_2$ is given by: $\bigl(at_1t_2,\, a(t_1+t_2)\bigr)$.
- If the tangents at $t_1$ and $t_2$ intersect at right angles ($90^\circ$), then $t_1 t_2 = -1$.
Equations of Normal
Normal at a Point $(x_1, y_1)$Topic 1
\begin{formulabox}[Point Form] \[ y - y_1 = -\frac{y_1}{2a}(x - x_1) \] \end{formulabox}
Normal in Parametric FormTopic 2
\begin{formulabox}[Parametric Form — at parameter $t$] \[ y + tx = 2at + at^3 \] \end{formulabox}
Normal in Slope FormTopic 3
\begin{formulabox}[Slope Form — slope $m$] \[ y = mx - 2am - am^3 \] The matching base foot of the normal vector evaluates coordinate-wise to: $\bigl(am^2,\, -2am\bigr)$. \end{formulabox}
Number of Normals from an External PointTopic 4
For a general external coordinate point $(h, k)$, the slope-form normal equation generates a cubic equation in terms of $m$: \[ am^3 + m(2a - h) + k = 0. \] Because it is a cubic equation, a maximum of three real normals can be drawn from an external point to a parabola.
\begin{importantbox}[Condition for Three Real Normals] Three distinct real normals can be drawn from an external point $(h, k)$ to the parabola $y^2 = 4ax$ if and only if: \[ h > 2a \quad \text{and} \quad k^2 < \frac{4}{27}\cdot\frac{(h-2a)^3}{a}. \] \end{importantbox}
Co-normal PointsTopic 5
If the three normals drawn at parameters $t_1, t_2,$ and $t_3$ are concurrent at a single point $(h,k)$, these parameters are called co-normal points. They satisfy the following properties derived from Vieta's formulas: \[ t_1 + t_2 + t_3 = 0, \quad t_1 t_2 + t_2 t_3 + t_3 t_1 = \frac{2a-h}{a}, \quad t_1 t_2 t_3 = -\frac{k}{a}. \]
Chord of the Parabola
Focal ChordTopic 1
A chord passing through the focus $(a, 0)$ is called a focal chord.
\begin{formulabox}[Properties of Focal Chord] If $t_1$ and $t_2$ represent the parameter endpoints of a focal chord: \[ t_1 \cdot t_2 = -1. \]- The semi-latus rectum is the harmonic mean of the focal segments: $\dfrac{1}{SP} + \dfrac{1}{SQ} = \dfrac{1}{a}$.
- Total length of a focal chord $= a\left(t - \dfrac{1}{t}\right)^2 = a\left(t + \dfrac{1}{t}\right)^2$, where $t = t_1$.
- The minimum length of a focal chord is $4a$ (the latus rectum).
Chord with a Given MidpointTopic 2
If a chord is bisected exactly at an interior point $M(h, k)$, its equation can be found using the $T = S_1$ formula: \begin{formulabox}[Equation of Chord with Midpoint $(h,k)$] \[ ky - 2a(x + h) = k^2 - 4ah \quad \Longleftrightarrow \quad T = S_1 \] where $T \equiv yy_1 - 2a(x+x_1)$ and $S_1 \equiv y_1^2 - 4ax_1$. \end{formulabox}
Chord of ContactTopic 3
The straight line connecting the two points of tangency where tangents drawn from an external point $P(x_1, y_1)$ touch the curve is called the chord of contact. \begin{formulabox}[Chord of Contact: $T = 0$] \[ y y_1 = 2a(x + x_1) \] \end{formulabox}
Pole and Polar
Pole and PolarTopic 1
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\begin{formulabox}[Polar of a Point $(x_1, y_1)$ w.r.t. $y^2 = 4ax$] \[ y y_1 = 2a(x + x_1) \quad \Longleftrightarrow \quad T = 0 \] The point $(x_1, y_1)$ is called the pole, and the resulting line equation is its polar. \end{formulabox}
\begin{property} Conjugate Points Property: If the polar line of a point $A$ passes through another point $B$, then the polar line of $B$ is guaranteed to pass through $A$. \end{property}
Subtangent and Subnormal
Subtangent and SubnormalTopic 1
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For the parabola $y^2 = 4ax$, geometric projections of the tangent and normal lines onto the axis of symmetry from any point $P(x_1, y_1)$ yield constant length properties:
\begin{formulabox}[Subtangent and Subnormal Lengths] \[ \text{Length of Subtangent} = 2x_1, \qquad \text{Length of Subnormal} = 2a \] \end{formulabox}
The length of the subnormal is constant and equal to the semi-latus rectum $2a$ for all points on the parabola.
Reflection Property of Parabola
Reflection Property of ParabolaTopic 1
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\begin{importantbox}[Reflection Property] An incoming ray travelling parallel to the axis of symmetry of a parabola passes through the focus after reflecting off the parabolic surface curve.
Equivalently: The tangent line drawn at any point $P$ makes equal angles with:- The focal radius line $SP$, and
- The horizontal line through $P$ drawn parallel to the axis of symmetry.
Common Tangents to Parabolas
Common Tangents to ParabolasTopic 1
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\begin{examplebox}[Common Tangents: $y^2 = 4ax$ and $x^2 = 4by$] Let the required common tangent have a slope $m$. \[ y = mx + \frac{a}{m} \quad \text{--- (Tangent equation template for } y^2=4ax \text{)} \] Now rearrange the standard vertical parabola tangent layout to match slope form: \[ x = \frac{y}{m} - bm^2 \implies y = mx + bm^3 \quad \text{--- (Tangent equation template for } x^2=4by \text{)} \] Equate the two expressions for the y-intercept constant to solve for $m$: \[ \frac{a}{m} = bm^3 \implies m^4 = \frac{a}{b} \implies m = \left(\frac{a}{b}\right)^{1/4}. \] \end{examplebox}
Important Results and JEE Tricks
Important Results and JEE TricksTopic 1
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\begin{warningbox}[JEE Important Results — Parabola]- The tangent drawn at a parameter point $t$ intersects the tangent at the vertex ($x=0$) at the coordinate point $(0, at)$.
- The orthocenter of the triangle formed by three tangent lines drawn to a parabola always lies on the directrix line curve.
- The circumcircle of the triangle formed by three tangents drawn to a parabola always passes through the focus $S(a,0)$.
- If the normal line drawn at parameter $t$ intersects the parabola again at a new parameter point $t'$, their relationship is given by: \[ t' = -t - \frac{2}{t}. \]
- Director Circle Property: A parabola has no director circle curve. The locus of the point of intersection of perpendicular tangents is the directrix line ($x = -a$).
- The area of a triangle inscribed inside the parabola $y^2 = 4ax$ with vertices at parameter points $t_1, t_2,$ and $t_3$ is: \[ \Delta = \frac{a^2}{2} |t_1 - t_2||t_2 - t_3||t_3 - t_1|. \]
Practice Problems (JEE Level)
Practice Problems (JEE Level)Topic 1
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- Find the angle subtended by the double ordinate of length $8a$ at the vertex of the standard parabola $y^2 = 4ax$.
- If $P$ and $Q$ represent the parameter endpoints of a focal chord of the parabola $y^2 = 4ax$ and $S$ is the focus, prove that $\dfrac{1}{SP} + \dfrac{1}{SQ} = \dfrac{1}{a}$.
- The normal line at a point $P$ on the parabola $y^2 = 4ax$ intersects the curve again at a point $Q$. Prove that the locus of the midpoint of the chord segment $PQ$ is given by the curve equation $y^2(y^2 + 2a^2) + 8a^4 = 0$. [JEE Advanced]
- Tangent lines are drawn from the external point $(-1, 2)$ to the parabola $y^2 = 4x$. Find the equation of the chord of contact and calculate its length.
- Three distinct real normals can be drawn to the parabola $y^2 = 4x$ through the point $(c, 0)$ lying on its axis of symmetry. Show that the parameter constant must satisfy $c > 2$.
- The angle subtended by the double ordinate of length $8a$ at the vertex of $y^2 = 4ax$ evaluates to:
- $90^\circ$
- $\tan^{-1}(2)$
- $2\tan^{-1}(2)$
- $45^\circ$
- If the chord of contact from $(-1, 2)$ to $y^2 = 4x$ has length $L$, the value of $L$ matches:
- $4$
- $2\sqrt{2}$
- $4\sqrt{2}$
- $8$
- Find the range of $c$ for which three distinct real normals can be drawn to $y^2 = 4x$ from $(c, 0)$:
- $c > 2$
- $c < 2$
- $c > 4$
- $c > 1$
- If a focal chord has segments $SP=4$ and $SQ$, and $a=2$, find the length of the segment $SQ$:
- $4$
- $2$
- $1$
- $8$
- The locus of the point of intersection of perpendicular tangents to $y^2 = 16x$ is:
- $x + 4 = 0$
- $x - 4 = 0$
- $y = 4$
- $x = 0$
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Quick Reference Card
Quick Reference CardTopic 1
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\begin{formulabox}[All Parabola Formulas at a Glance] Standard Parabola Layout Format: $y^2 = 4ax$; $\;a = $ distance from vertex to focus.
\medskip
| Geometric Operational Form | Algebraic Formula / Line Equation |
| Tangent Line (Point Form): | $y y_1 = 2a(x + x_1)$ |
| Tangent Line (Parametric Form): | $ty = x + at^2$ |
| Tangent Line (Slope Form): | $y = mx + a/m$ |
| Normal Line (Point Form): | $y - y_1 = -\dfrac{y_1}{2a}(x-x_1)$ |
| Normal Line (Parametric Form): | $y + tx = 2at + at^3$ |
| Normal Line (Slope Form): | $y = mx - 2am - am^3$ |
| Chord of Contact Line Equation: | $y y_1 = 2a(x+x_1)$ |
| Chord Line with Midpoint $(h,k)$: | $ky - 2ax = k^2 - 2ah \implies T = S_1$ |
| Focal Chord Boundary Condition: | $t_1 \cdot t_2 = -1$ |
| Normal Re-intersection Condition: | $t' = -t - 2/t$ |
| Co-normal Roots Sum Property: | $t_1 + t_2 + t_3 = 0$ |
Solved Examples
Worked ExamplesTopic 1
Example 1 — Tangents from an External Point
Find the equations of the tangents drawn to the parabola $y^2 = 8x$ from the external point $(2, 3)$.
Show solution
Here $4a = 8 \implies a = 2$. Write down the slope-form tangent equation template: \[ y = mx + \frac{2}{m}. \] Since the tangent line passes through the external point $(2, 3)$, substitute these coordinates into the template to solve for $m$: \[ 3 = 2m + \frac{2}{m} \implies 2m^2 - 3m + 2 = 0. \] Evaluate the discriminant of this quadratic equation: \[ D = (-3)^2 - 4(2)(2) = 9 - 16 = -7 < 0. \] Because the discriminant is strictly negative, the slopes are imaginary, meaning no real tangents can be drawn from this point.
\smallskip Key Check: For real tangents to be drawn from a point $(h, k)$ to the parabola $y^2 = 4ax$, the point must lie strictly outside the curve surface ($k^2 > 4ah$). Here, checking the point gives $3^2 > 4(2)(2) \implies 9 > 16$, which is false. This confirms that the point lies inside the parabola, where no real tangents can exist.
Example 2 — Normal Meeting the Parabola Again
If the normal line to the parabola $y^2 = 4x$ drawn at parameter $t = 2$ intersects the curve again at a new parameter point $t'$, find the value of $t'$ and the coordinates of the intersection point.
Show solution
Here $a = 1$. Apply the normal re-intersection parameter relationship formula: \[ t' = -t - \frac{2}{t} = -2 - \frac{2}{2} = -2 - 1 = -3. \] Now use the parametric equations to find the coordinates of this endpoint: \[ x' = a(t')^2 = 1(-3)^2 = 9, \quad y' = 2a(t') = 2(1)(-3) = -6. \] The normal line intersects the curve again at the coordinate position $(9, -6)$.
Example 3 — Length of a Focal Chord
Find the total length of a focal chord of the parabola $y^2 = 12x$ if one of its endpoints is parameterized at $t = 2$.
Show solution
Extract the parameter value: $4a = 12 \implies a = 3$. Apply the focal chord length formula directly: \[ \text{Length} = a\left(t + \dfrac{1}{t}\right)^2 = 3\left(2 + \dfrac{1}{2}\right)^2 = 3 \cdot \left(\dfrac{5}{2}\right)^2 = 3 \cdot \dfrac{25}{4} = \dfrac{75}{4}\text{ units}. \]