Vidaara.orgClass 10 · Mathematics
CodeVID-M10-10-SEC-01
Area of a Sector — Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
Area of a sector $=$
- A.$\tfrac{\theta}{360^\circ}\pi r^2$
- B.$\tfrac{\theta}{360^\circ}2\pi r$
- C.$\pi r^2$
- D.$\theta r^2$
2.
Length of an arc $=$
- A.$\tfrac{\theta}{360^\circ}\pi r^2$
- B.$\tfrac{\theta}{360^\circ}2\pi r$
- C.$2\pi r$
- D.$\pi r$
3.
A quadrant is a sector of angle:
- A.$45^\circ$
- B.$90^\circ$
- C.$180^\circ$
- D.$360^\circ$
4.
A semicircle is a sector of angle:
- A.$90^\circ$
- B.$180^\circ$
- C.$270^\circ$
- D.$360^\circ$
5.
The whole circle corresponds to $\theta=$
- A.$90^\circ$
- B.$180^\circ$
- C.$360^\circ$
- D.$270^\circ$
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Find the area of a sector with $\theta=90^\circ,\ r=14$ ($\pi=\tfrac{22}{7}$).
7.
Find the arc length for $\theta=60^\circ,\ r=21$.
8.
Find the area of a quadrant of radius $7$.
9.
Find the sector area for $\theta=120^\circ,\ r=6$ ($\pi=3.14$).
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Find the area of a sector of angle $60^\circ$ in a circle of radius $6$ cm ($\pi=\tfrac{22}{7}$).
11.
Find the arc length of a $90^\circ$ sector of radius $14$ cm.
12.
A sector has area equal to $\tfrac16$ of a circle of radius $12$. Find its angle.
13.
Find the perimeter of a quadrant of radius $7$ cm.
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
A sector of a circle of radius $21$ cm has an angle of $120^\circ$. Find its area and arc length ($\pi=\tfrac{22}{7}$).
15.
The minute hand of a clock is $14$ cm long. Find the area it sweeps in $15$ minutes.
Answer Key
Section A — Multiple Choice Questions
- (A) $\tfrac{\theta}{360^\circ}\pi r^2$
- (B) $\tfrac{\theta}{360^\circ}2\pi r$
- (B) $90^\circ$
- (B) $180^\circ$
- (C) $360^\circ$
Section B — Short Answer (2 marks)
- $154$ cm$^2$.
- $22$ cm.
- $38.5$ cm$^2$.
- $37.68$ cm$^2$.
Section C — Short Answer (3 marks)
- $\tfrac{132}{7}\approx18.86$ cm$^2$.
- $22$ cm.
- $60^\circ$.
- $25$ cm.
Section D — Long Answer (5 marks)
- Area $462$ cm$^2$, arc $44$ cm.
- $154$ cm$^2$.
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