Vidaara.orgClass 10 · Mathematics
CodeVID-M10-11-FRU-01
Frustum of a Cone — Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
A frustum results from a cut:
- A.through the apex
- B.parallel to the base
- C.perpendicular
- D.oblique
2.
Volume of a frustum $=$
- A.$\tfrac13\pi h(R^2+Rr+r^2)$
- B.$\pi h(R+r)$
- C.$\tfrac13\pi r^2h$
- D.$\pi Rl$
3.
Slant height of a frustum $=$
- A.$\sqrt{h^2+R^2}$
- B.$\sqrt{h^2+(R-r)^2}$
- C.$h+R$
- D.$\sqrt{R^2-r^2}$
4.
CSA of a frustum $=$
- A.$\pi(R+r)l$
- B.$\pi(R-r)l$
- C.$2\pi rl$
- D.$\pi r^2$
5.
A frustum has two circular ends of radii:
- A.$R$ only
- B.$R$ and $r$
- C.$r$ only
- D.equal radii
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Find the slant height if $h=4,\ R=5,\ r=2$.
7.
State the volume formula of a frustum.
8.
Find the CSA of a frustum with $R=6,\ r=3,\ l=5$.
9.
Find $R+r$ for a frustum with radii $4$ and $2$.
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Find the volume of a frustum with $R=10,\ r=4,\ h=9$ ($\pi=3.14$).
11.
Find the slant height of a frustum with $R=8,\ r=5,\ h=4$.
12.
Find the CSA of a frustum with $R=6,\ r=3$ and slant height $5$.
13.
A bucket (frustum) has radii $15$ and $5$ and height $24$. Find its slant height.
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
A bucket is a frustum with radii $20$ cm and $12$ cm and height $15$ cm. Find its capacity ($\pi=3.14$).
15.
The radii of the ends of a frustum are $14$ cm and $6$ cm, and its height is $6$ cm. Find its curved surface area ($\pi=\tfrac{22}{7}$).
Answer Key
Section A — Multiple Choice Questions
- (B) parallel to the base
- (A) $\tfrac13\pi h(R^2+Rr+r^2)$
- (B) $\sqrt{h^2+(R-r)^2}$
- (A) $\pi(R+r)l$
- (B) $R$ and $r$
Section B — Short Answer (2 marks)
- $5$.
- $\tfrac13\pi h(R^2+Rr+r^2)$.
- $45\pi$.
- $6$.
Section C — Short Answer (3 marks)
- $\approx1469.52$ cm$^3$.
- $5$.
- $45\pi$.
- $26$ cm.
Section D — Long Answer (5 marks)
- $\approx12308.8$ cm$^3$ ($\approx12.3$ litres).
- $\approx628.57$ cm$^2$.
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