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Vidaara.orgClass 10 · Mathematics
CodeVID-M10-01-EDL-01
Euclid’s Division Lemma — Assignment
Chapter: Number Systems
Topic: Euclid’s Division Lemma
Maximum Marks: 35
Time: 75 minutes
Name: ____________________ Roll No.: __________ Date: ____________

General Instructions

  • All questions are compulsory.
  • Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
  • Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions 5 × 1 = 5 marks
1.
Euclid's lemma: $a=bq+r$ with:
  • A.$0\le r
  • B.$0
  • C.$r=0$
  • D.$r>b$
2.
The HCF of $6$ and $8$ is:
  • A.$1$
  • B.$2$
  • C.$4$
  • D.$24$
3.
HCF$(18,24)=$
  • A.$3$
  • B.$6$
  • C.$12$
  • D.$2$
4.
The HCF of two coprime numbers is:
  • A.$0$
  • B.$1$
  • C.$2$
  • D.their LCM
5.
HCF$(0,5)=$
  • A.$0$
  • B.$5$
  • C.$1$
  • D.undefined
Section B — Short Answer (2 marks) 4 × 2 = 8 marks
6.
Find the HCF of $12$ and $18$.
7.
Write $17=5q+r$ using Euclid's lemma.
8.
Find HCF$(36,84)$.
9.
Are $8$ and $15$ coprime?
Section C — Short Answer (3 marks) 4 × 3 = 12 marks
10.
Find HCF$(135,225)$ using Euclid's algorithm.
11.
Find HCF$(196,38220)$.
12.
Show that any positive odd integer is of the form $4q+1$ or $4q+3$.
13.
Find the largest number dividing $70$ and $125$ leaving remainders $5$ and $8$.
Section D — Long Answer (5 marks) 2 × 5 = 10 marks
14.
Find the HCF of $867$ and $255$ using Euclid's division algorithm.
15.
Find the largest number which divides $2053$ and $967$ leaving remainders $5$ and $7$ respectively.

Answer Key

Section A — Multiple Choice Questions
  1. (A) $0\le r
  2. (B) $2$
  3. (B) $6$
  4. (B) $1$
  5. (B) $5$
Section B — Short Answer (2 marks)
  1. $6$.
  2. $17=5\cdot3+2$.
  3. $12$.
  4. Yes.
Section C — Short Answer (3 marks)
  1. $45$.
  2. $196$.
  3. Established (odd integers leave remainder $1$ or $3$ on division by $4$).
  4. $13$.
Section D — Long Answer (5 marks)
  1. $51$.
  2. $64$.
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