Vidaara.orgClass 12 · Mathematics
CodeVID-M12-11-LIN-01
Equation of a Line in Space — Assignment
Name: ____________________
Roll No.: __________
Date: ____________
General Instructions
- All questions are compulsory.
- Section A carries 1 mark each, Section B 2 marks, Section C 3 marks and Section D 5 marks.
- Show all working for Sections B, C and D. Only final answers are given at the end — for full solutions, raise your doubts with your teacher.
Section A — Multiple Choice Questions
5 × 1 = 5 marks
1.
The vector equation of a line is:
- A.$\vec r=\vec a+\lambda\vec b$
- B.$\vec r\cdot\vec n=d$
- C.$\vec r=\vec a\times\vec b$
- D.$|\vec r|=1$
2.
In $\dfrac{x-1}{2}=\dfrac{y+3}{-1}=\dfrac{z}{4}$, the direction ratios are:
- A.$(1,-3,0)$
- B.$(2,-1,4)$
- C.$(1,3,0)$
- D.$(2,1,4)$
3.
A point on $\dfrac{x-1}{2}=\dfrac{y+3}{-1}=\dfrac{z}{4}$ is:
- A.$(2,-1,4)$
- B.$(1,-3,0)$
- C.$(1,3,0)$
- D.$(0,0,0)$
4.
The line through $(1,2,3),(2,4,5)$ has DRs:
- A.$(1,2,2)$
- B.$(3,6,8)$
- C.$(1,1,1)$
- D.$(2,4,5)$
5.
In Cartesian form, the denominators give the:
- A.points
- B.direction ratios
- C.angles
- D.intercepts
Section B — Short Answer (2 marks)
4 × 2 = 8 marks
6.
Write the vector equation of the line through $(1,0,2)$ with direction $\hat i+\hat j-\hat k$.
7.
Write the Cartesian equation of the line through $(2,-1,3)$ with DRs $1,2,2$.
8.
Write the Cartesian equation of the line through $(1,2,3)$ and $(2,4,5)$.
9.
From $\dfrac{x-1}{2}=\dfrac{y+3}{-1}=\dfrac{z}{4}$, write a point and the DRs.
Section C — Short Answer (3 marks)
4 × 3 = 12 marks
10.
Find the vector equation of the line through $(2,-1,1)$ and $(4,1,3)$.
11.
Find the Cartesian equation of the line through the origin with DRs $3,-1,2$.
12.
Does the point $(3,2,1)$ lie on $\dfrac{x-1}{2}=\dfrac{y+1}{3}=\dfrac{z}{1}$?
13.
Convert $\vec r=(\hat i+\hat j)+\lambda(2\hat i-\hat j+\hat k)$ to Cartesian form.
Section D — Long Answer (5 marks)
2 × 5 = 10 marks
14.
Find the vector and Cartesian equations of the line through $(1,2,3)$ parallel to $\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{6}$.
15.
Show that the line through $(1,-1,2),(3,4,-2)$ is perpendicular to the line through $(0,3,2),(3,5,6)$.
Answer Key
Section A — Multiple Choice Questions
- (A) $\vec r=\vec a+\lambda\vec b$
- (B) $(2,-1,4)$
- (B) $(1,-3,0)$
- (A) $(1,2,2)$
- (B) direction ratios
Section B — Short Answer (2 marks)
- $\vec r=(\hat i+2\hat k)+\lambda(\hat i+\hat j-\hat k)$.
- $\dfrac{x-2}{1}=\dfrac{y+1}{2}=\dfrac{z-3}{2}$.
- $\dfrac{x-1}{1}=\dfrac{y-2}{2}=\dfrac{z-3}{2}$.
- Point $(1,-3,0)$; DRs $(2,-1,4)$.
Section C — Short Answer (3 marks)
- $\vec r=(2\hat i-\hat j+\hat k)+\lambda(\hat i+\hat j+\hat k)$.
- $\dfrac{x}{3}=\dfrac{y}{-1}=\dfrac{z}{2}$.
- Yes.
- $\dfrac{x-1}{2}=\dfrac{y-1}{-1}=\dfrac{z}{1}$.
Section D — Long Answer (5 marks)
- $\vec r=(\hat i+2\hat j+3\hat k)+\lambda(2\hat i+3\hat j+6\hat k)$; $\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{6}$.
- Perpendicular (dot product $=0$).
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