NEET (UG)

Practice Test 1 — Amines

12 questions • 18 minutes • auto-graded with full solutions
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Section A — MCQ (Single Correct & Statement-based)
Question 1

Amines are classified as $1^\circ$, $2^\circ$, $3^\circ$ by the number of:

Solution: By carbons attached to N.
Question 2

The Gabriel synthesis cannot prepare:

Solution: It fails for aromatic amines like aniline.
Question 3

The Hofmann bromamide degradation gives an amine with:

Solution: Amide loses one carbon.
Question 4

Statements: (I) Aniline is less basic than ethylamine. (II) Aniline's lone pair is delocalised into the ring. Which is/are correct?

Solution: Both correct; (II) is the reason for (I).
Question 5

The strongest base in water is:

Solution: Dimethylamine: best balance of $+\text{I}$ and solvation.
Question 6

The carbylamine test detects:

Solution: Foul isocyanide forms only with $1^\circ$ amines.
Question 7

Aniline + $\text{NaNO}_2$/HCl at 273–278 K gives:

Solution: Cold diazotisation.
Question 8

Coupling of a diazonium salt with phenol gives:

Solution: Azo compound ($-\text{N}=\text{N}-$).
Section B — Assertion & Reason
Question 9

A: Aniline is a weaker base than ethylamine.
R: In aniline the nitrogen lone pair is delocalised into the benzene ring.

Solution: Delocalisation reduces lone-pair availability, lowering basicity — R explains A.
Question 10

A: A diazonium salt is prepared at 273–278 K.
R: Arenediazonium salts are unstable and decompose if warmed.

Solution: The low temperature is needed precisely because the salt is heat-sensitive — R explains A.
Question 11

A: The carbylamine reaction is given only by primary amines.
R: Primary amines react with chloroform and alcoholic KOH to form foul-smelling isocyanides.

Solution: Only primary amines form the isocyanide, which is exactly why it is a test for them — R explains A.
Question 12

A: Reduction of a nitrile gives an amine with one more carbon than the nitrile's R group.
R: The nitrile carbon (–C≡N) becomes the –CH₂– carbon of the amine.

Solution: The nitrile's own carbon is retained as the new CH₂ next to N, so the amine has one extra carbon — R explains A.