A particle executes SHM with amplitude A = 5 cm and time period T = 2 s — JEE Physics
A particle executes SHM with amplitude $A = 5$ cm and time period $T = 2$ s. Find the maximum velocity and maximum acceleration.
1 Answer
VAVidaara Admin
✓ Vidaara Team
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· 2mo ago
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$$\omega = \frac{2\pi}{T} = \pi rad/s$$
$$v_{max} = A\omega = 5\pi cm/s \approx 15.7 cm/s$$
$$a_{max} = A\omega^2 = 5\pi^2 cm/s^2 \approx 49.3 cm/s^2$$
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Discussion (4)
GP
Why do we take the positive value only in the last step?
SJ
Why do we take the positive value only in the last step?
AK
Saved me before my mock test. Much clearer than my coaching notes.
MT
Can someone explain why we ignore the other root here?