JEE physics

A string of length $L = 1$ m is fixed at both ends. Find the first three harmonics (natural frequencies) if the wave speed is $v = 200$ m/s.

EEthanWalker47 Asked 2mo ago 1,065 views 1 answer

A string of length $L = 1$ m is fixed at both ends. Find the first three harmonics (natural frequencies) if the wave speed is $v = 200$ m/s.

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2mo ago ▲ 34

For fixed-fixed string, $\lambda_n = \dfrac{2L}{n}$, so $f_n = \dfrac{nv}{2L}$:

$$f_1 = \frac{1 \times 200}{2} = 100 Hz$$

$$f_2 = 200 Hz, \quad f_3 = 300 Hz$$

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Discussion (3)

K
Can someone explain why we ignore the other root here?
KasunSilva64 · 2mo ago
SJ
Thanks a ton, I was stuck on this exact problem for an hour.
Shruti Jain · 2mo ago
VA
Good follow-up questions — remember to always state your assumptions in the JEE subjective section.
Vidaara Admin · Vidaara Team · 1mo ago
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