The total revenue in Rupees received from the sale of $x$ units of a product is given by $R(x) = 13{x^2} + 2x + 15$. Find the marginal revenue when $x = 7$.
The total revenue in Rupees received from the sale of $x$ units of a product is given by $R(x) = 13{x^2} + 2x + 15$. Find the marginal revenue when $x = 7$.
Official Solution
We have, $R(x) = 13{x^2} + 26x + 15$ ….(i)
Differentiating (i) wr.t. $x$, we have.
Marginal revenue $= \cfrac{{dR}}{{dx}} = 13 \times 2x + 26 = 26x + 26$
Therefore, ${\left( {\cfrac{{dR}}{{dx}}} \right)_{x = 7}} = 26 \times 7 + 26 = 208$
$\Rightarrow$ Marginal revenue (when $x = 7$)$= Rs208$ .
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