The total revenue in Rupees received from the sale of $x$ units of a product is given by$R\left( x \right) = 3{x^2} + 36x + 5$. The marginal revenue, when $x = 15$ is
(A) $116$
(B) $96$
(C) $90$
(D) $126$
The total revenue in Rupees received from the sale of $x$ units of a product is given by$R\left( x \right) = 3{x^2} + 36x + 5$. The marginal revenue, when $x = 15$ is
(A) $116$
(B) $96$
(C) $90$
(D) $126$
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
Option D is correct
We have, $R(x) = 3{x^2} + 36x + 5$ …(i)
Differentiating (i) w.r.t. $x$, we get,
marginal revenue $\cfrac{{dR}}{{dx}} = \cfrac{d}{{dx}}(3{x^2} + 36x + 5) = 6x + 36$
$= {\left( {\cfrac{{dR}}{{dx}}} \right)_{x = 15}} = 6 \times 15 + 36 = 126$
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