class 12 maths application of derivatives

The radius of a circle is increasing at the rate of $0.7{\rm{cm/s}}$ . What is the rate of increase of its circumference?

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📘 Application of Derivatives NCERT Ex.6.1,Q.No. 6,Page 198 SA

The radius of a circle is increasing at the rate of $0.7{\rm{cm/s}}$ . What is the rate of increase of its circumference?

Official Solution

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Let at any instant of time $t$, the radius of the circle be $r$ and its circumference be $C$, then $C = 2\pi r$ …(i)

Differentiating (i) w.r.t. $t$, we get
$\cfrac{{dC}}{{dt}} = 2\pi \cfrac{{dr}}{{dt}} = 2\pi (0.7){\rm{cm/sec}}$
$= (1.4\pi ){\rm{cm/sec}}$

Therefore the rate of increase of circumference $= (1.4\pi ){\rm{cm/sec}}$

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