$\cfrac{{{e^x}}}{{\sin x}}$
$\cfrac{{{e^x}}}{{\sin x}}$
Official Solution
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NCERT & Exemplar
Let $y = \cfrac{{{e^x}}}{{\sin x}}$
therefore, $\cfrac{{dy}}{{dx}} = \cfrac{d}{{dx}}\left( {\cfrac{{{e^x}}}{{\sin x}}} \right) = \cfrac{{\sin x\cfrac{d}{{dx}}({e^x}) - {e^x}\cfrac{d}{{dx}}(\sin x)}}{{{{\sin }^2}x}}$
$= \cfrac{{\sin x \cdot {e^x} - {e^x} \cdot \cos x}}{{{{\sin }^2}x}} = \cfrac{{{e^x}(\sin x - \cos x)}}{{{{\sin }^2}x}},x \ne n\pi ,n \in Z$
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