class 12 maths continuity and differentiability

$\cfrac{{{e^x}}}{{\sin x}}$

VAVidaara Admin Asked 9d ago 0 views 0 answers
📘 Continuity and Differentiability NCERT Ex.5.4 ,Q.1,Page 174 SA

$\cfrac{{{e^x}}}{{\sin x}}$

Official Solution

VVidaara Team ✓ Verified solution NCERT & Exemplar

Let $y = \cfrac{{{e^x}}}{{\sin x}}$

therefore, $\cfrac{{dy}}{{dx}} = \cfrac{d}{{dx}}\left( {\cfrac{{{e^x}}}{{\sin x}}} \right) = \cfrac{{\sin x\cfrac{d}{{dx}}({e^x}) - {e^x}\cfrac{d}{{dx}}(\sin x)}}{{{{\sin }^2}x}}$

$= \cfrac{{\sin x \cdot {e^x} - {e^x} \cdot \cos x}}{{{{\sin }^2}x}} = \cfrac{{{e^x}(\sin x - \cos x)}}{{{{\sin }^2}x}},x \ne n\pi ,n \in Z$

View the full step-by-step solution page & related questions →

Community Answers (0)

Log in to post your own answer or join the discussion.

Discussion (0)

No comments yet — start the discussion.

← Back to all questions