class 12 maths determinants

(i) $\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}{\cos \theta }&{ - \sin \theta }\\{\sin \theta }&{\cos \theta }\end{array}} \right|$ (ii) $\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}{{x^2} - x + 1}&{x - 1}\\{x + 1}&{x + 1}\end{array}} \right|$

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📘 Determinants NCERT,Ex.4.1,Q.2,Page.108 SA

(i) $\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}{\cos \theta }&{ - \sin \theta }\\{\sin \theta }&{\cos \theta }\end{array}} \right|$ (ii) $\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}{{x^2} - x + 1}&{x - 1}\\{x + 1}&{x + 1}\end{array}} \right|$

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(i)$\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}{\cos \theta }&{ - \sin \theta }\\{\sin \theta }&{\cos \theta }\end{array}} \right|$

$= \cos \theta \times \cos \theta - (\sin \theta ) \times ( - \sin \theta ) = {\cos ^2}\theta + {\sin ^2}\theta = 1$

(ii) $\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}{{x^2} - x + 1}&{x - 1}\\{x + 1}&{x + 1}\end{array}} \right| = ({x^2} - x + 1)(x + 1)(x + 1)(x - 1)$

$= {x^3} + 1 - ({x^2} - 1) = {x^3} + 1 - {x^2} + 1 = {x^3} - {x^2} + 2$

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