class 12 maths determinants

(i) $\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}2&{ - 4}\\0&3\end{array}} \right|$
(ii) $\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}a&c\\b&d\end{array}} \right|$

VAVidaara Admin Asked 8d ago 0 views 0 answers
📘 Determinants NCERT,Ex.4.4,Q.1,Page.126 SA

(i) $\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}2&{ - 4}\\0&3\end{array}} \right|$
(ii) $\left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}a&c\\b&d\end{array}} \right|$

Official Solution

VVidaara Team ✓ Verified solution NCERT & Exemplar

(i) Let $P = \left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}2&{ - 4}\\0&3\end{array}} \right|$

Minor of the element ${a_{ij}}$ is ${M_{ij}},$.

Here,
${M_{11}} = 3,{M_{12}} = 0,{M_{21}} = - 4,{M_{22}} = 2$

For cofactors, we know that ${P_{ij}} = {( - 1)^{i + j}}{M_{ij}}$

$\therefore$ ${P_{11}} = 3,{P_{12}} = - 0 = 0,{P_{21}} = 4,{P_{22}} = 3$

(ii) Let $P = \left| {\begin{array}{rrrrrrrrrrrrrrrrrrrr}a&c\\b&d\end{array}} \right|$ ,

Minor of the element ${a_{ij}}$ is ${M_{ij}},$

Here ${M_{11}} = d,{M_{12}} = b,{M_{21}} = c,{M_{22}} = a$

For cofactors,

we know that ${P_{ij}} = {( - 1)^{i + j}}{M_{ij}}$

$\therefore {P_{11}} = d,{P_{12}} = - b,{P_{21}} = - c,{P_{22}} = a$

View the full step-by-step solution page & related questions →

Community Answers (0)

Log in to post your own answer or join the discussion.

Discussion (0)

No comments yet — start the discussion.

← Back to all questions