$y = a{e^{mx}} + b{e^{ - mx}}$
satisfies which of the following differential equation?
$y = a{e^{mx}} + b{e^{ - mx}}$
satisfies which of the following differential equation?
Official Solution
Given that, $y = a{e^{mx}} + b{e^{ - mx}}$
On differentiating both sides w.r.t. $x$,
we get
$\frac{{dy}}{{dx}} = ma{e^{mx}} - bm{e^{ - mx}}$
Again, differentiating both sides w.r.t. $x$,
we get
$\frac{{{d^2}y}}{{d{x^2}}} = {m^2}a{e^{mx}} + b{m^2}{e^{ - mx}}$
$\Rightarrow$ $\frac{{{d^2}y}}{{d{x^2}}} = {m^2}\left( {a{e^{mn}} + b{e^{ - mn}}} \right)$
$\Rightarrow$ $\frac{{{d^2}y}}{{d{x^2}}} = {m^2}y$
$\Rightarrow$ $\frac{{{d^2}y}}{{d{x^2}}} - {m^2}y = 0$
No comments yet — start the discussion.