Which of the following differential equations has y = x as one of its particular solution? y d x 2 - x 2 dx + xy = x y d x 2 + x dx + xy = x y d x 2 - x 2 dx + xy = 0 y d x 2 + x 2 dx + xy = 0

Option c is correct We have y = x dx = 1 and y d x 2 = 0 which satisfy y d x 2 - x 2 dx + xy = 0 Exercise-9.4

class 12 maths differential equations

Which of the following differential equations has $y = x$ as one of its particular solution?
• $\cfrac{{{d^2}y}}{{d{x^2}}} - {x^2}\cfrac{{dy}}{{dx}} + xy = x$
• $\cfrac{{{d^2}y}}{{d{x^2}}} + x\cfrac{{dy}}{{dx}} + xy = x$
• $\cfrac{{{d^2}y}}{{d{x^2}}} - {x^2}\cfrac{{dy}}{{dx}} + xy = 0$
• $\cfrac{{{d^2}y}}{{d{x^2}}} + {x^2}\cfrac{{dy}}{{dx}} + xy = 0$

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📘 Differential Equations NCERT Ex.9.3,Q.12,Page 391 SA

Which of the following differential equations has $y = x$ as one of its particular solution?

• $\cfrac{{{d^2}y}}{{d{x^2}}} - {x^2}\cfrac{{dy}}{{dx}} + xy = x$

• $\cfrac{{{d^2}y}}{{d{x^2}}} + x\cfrac{{dy}}{{dx}} + xy = x$

• $\cfrac{{{d^2}y}}{{d{x^2}}} - {x^2}\cfrac{{dy}}{{dx}} + xy = 0$

• $\cfrac{{{d^2}y}}{{d{x^2}}} + {x^2}\cfrac{{dy}}{{dx}} + xy = 0$

VVidaara Team ✓ Verified solution NCERT & Exemplar

Option c is correct

We have $y = x \Rightarrow \cfrac{{dy}}{{dx}} = 1$ and $\cfrac{{{d^2}y}}{{d{x^2}}} = 0$

which satisfy $\cfrac{{{d^2}y}}{{d{x^2}}} - {x^2}\cfrac{{dy}}{{dx}} + xy = 0$

Exercise-9.4

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