Which of the following is a homogeneous differential equation?
• $(4x + 6y + 5)dy - (3y + 2x + 4)dx = 0$
• $(xy)dx - ({x^3} + {y^3})dy = 0$
• $({x^3} + 2{y^2})dx + 2xydy = 0$
• ${y^2}dx + ({x^2} - xy - {y^2})dy = 0$
Which of the following is a homogeneous differential equation?
• $(4x + 6y + 5)dy - (3y + 2x + 4)dx = 0$
• $(xy)dx - ({x^3} + {y^3})dy = 0$
• $({x^3} + 2{y^2})dx + 2xydy = 0$
• ${y^2}dx + ({x^2} - xy - {y^2})dy = 0$
Official Solution
Option d is correct
Here ${y^2}dx + ({x^2} - xy - {y^2})dy = 0$
$\Rightarrow \cfrac{{dy}}{{dx}} = - \cfrac{{{y^2}}}{{{x^2} - xy - {y^2}}} = \cfrac{{{y^2}}}{{{y^2} + xy - {x^2}}}$
Now, $f(x,y) = \cfrac{{{y^2}}}{{{y^2} + xy - {x^2}}}$
$\therefore$ $f(\lambda x,\;\lambda y) = \cfrac{{{\lambda ^2}{y^2}}}{{{\lambda ^2}{y^2} + (\lambda x)(\lambda y) - {\lambda ^2}{y^2}}}$
$= {\lambda ^0}\left( {\cfrac{{{y^2}}}{{{y^2} + xy - {x^2}}}} \right) = {\lambda ^0}f(x,y)$
$\therefore$ $f(x,\;y)$ is homogeneous function of degree zero.
So, (1) is homogeneous differential equation.
Exercise-9.6
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