class 12 maths differential equations

Which of the following is a homogeneous differential equation?

• $(4x + 6y + 5)dy - (3y + 2x + 4)dx = 0$

• $(xy)dx - ({x^3} + {y^3})dy = 0$

• $({x^3} + 2{y^2})dx + 2xydy = 0$

• ${y^2}dx + ({x^2} - xy - {y^2})dy = 0$

VAVidaara Admin Asked 8d ago 0 views 0 answers
📘 Differential Equations NCERT Ex.9.6,Q.17,Page 406 SA

Which of the following is a homogeneous differential equation?

• $(4x + 6y + 5)dy - (3y + 2x + 4)dx = 0$

• $(xy)dx - ({x^3} + {y^3})dy = 0$

• $({x^3} + 2{y^2})dx + 2xydy = 0$

• ${y^2}dx + ({x^2} - xy - {y^2})dy = 0$

Official Solution

VVidaara Team ✓ Verified solution NCERT & Exemplar

Option d is correct

Here ${y^2}dx + ({x^2} - xy - {y^2})dy = 0$

$\Rightarrow \cfrac{{dy}}{{dx}} = - \cfrac{{{y^2}}}{{{x^2} - xy - {y^2}}} = \cfrac{{{y^2}}}{{{y^2} + xy - {x^2}}}$

Now, $f(x,y) = \cfrac{{{y^2}}}{{{y^2} + xy - {x^2}}}$

$\therefore$ $f(\lambda x,\;\lambda y) = \cfrac{{{\lambda ^2}{y^2}}}{{{\lambda ^2}{y^2} + (\lambda x)(\lambda y) - {\lambda ^2}{y^2}}}$

$= {\lambda ^0}\left( {\cfrac{{{y^2}}}{{{y^2} + xy - {x^2}}}} \right) = {\lambda ^0}f(x,y)$

$\therefore$ $f(x,\;y)$ is homogeneous function of degree zero.

So, (1) is homogeneous differential equation.

Exercise-9.6

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