$\cfrac{x}{{9 - 4{x^2}}}$
$\cfrac{x}{{9 - 4{x^2}}}$
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
: Let$I = \int {\cfrac{x}{{9 - 4{x^2}}}dx}$
Put $9 - 4{x^2} = t$ $\Rightarrow$ $- 8x\,dx = dt$
$\therefore$ $I = - \cfrac{1}{8}\int {\cfrac{{dt}}{t}} = - \cfrac{1}{8}\log \left| t \right| + C = \cfrac{1}{8}\log \cfrac{1}{{\left| t \right|}} + C$
$= \cfrac{1}{8}\log \cfrac{1}{{\left| {9 - 4{x^2}} \right|}} + C$
Community Answers (0)
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.