$\cot x\log \sin x$
$\cot x\log \sin x$
Official Solution
VVidaara Team
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NCERT & Exemplar
: Let$I = \int {\cot x\log \sin x} dx$
Put $\log \sin x = t$ $\Rightarrow$ $\cfrac{1}{{\sin x}}\cos xdx = dt$
$\Rightarrow$ $\cot x\,dx = dt$
$\therefore$ $I = \int {t\,dt} = \cfrac{{{t^2}}}{2} + C = \cfrac{1}{2}{\left( {\log \sin x} \right)^2} + C$
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