: Let I = x + x x )dx Put 1 + x = t x dx = dt I = x ( 1 + x ) dx = t dt = t + C = ( 1 + x ) + C

class 12 maths integrals

$\cfrac{1}{{x + x\log x}}$

VAVidaara Admin Asked 8d ago 0 views 0 answers

📘 Integrals NCERT,ex.7.2,Q.3,Page 304 SA

Official Solution

VVidaara Team ✓ Verified solution NCERT & Exemplar

: Let $I = \int {\left( {\cfrac{1}{{x + x\log x}}} \right)dx}$
Put $1 + \log x = t$ $\Rightarrow$ $\cfrac{1}{x}dx = dt$

$\therefore$ $I = \int {\cfrac{1}{{x\left( {1 + \log x} \right)}}dx} = \int {\cfrac{1}{t}dt} = \log t + C = \log \left( {1 + \log x} \right) + C$

Log in to post your own answer or join the discussion.

No comments yet — start the discussion.