class 12 maths inverse trigonometric functions

${\tan ^{ - 1}}( - 1)$

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📘 Inverse Trigonometric Functions NCERT Ex. 2.1, Q. 6 , Page 41 SA

${\tan ^{ - 1}}( - 1)$

Official Solution

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Let ${\tan ^{ - 1}}( - 1) = x \Rightarrow - 1 = \tan x$
As we know that the range of principal value branch of ${\tan ^{ - 1}}$ is $\left( { - \frac{\pi }{2},\;\frac{\pi }{2}} \right)$

Then, $- 1 = \tan \left( { - \frac{\pi }{4}} \right)where - \frac{\pi }{4} \in \left( { - \frac{\pi }{2},\;\frac{\pi }{2}} \right)$

Hence, the principal value of ${\tan ^{ - 1}}( - 1)\;is\; - \frac{\pi }{4}.$

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