Corner points of the feasible region determined by the system of linear constraints are (0,3),(1,1) and (3,0) . Let $Z = px + qy$, where $p,$ $q > 0$. Condition on $p$ and $q$, so that the minimum of $Z$ occurs at (3,0) and (1,1) is

So, condition of $p$ and $q$,

so that the minimum of $Z$ occurs at (3,0) and (1,1) is

$p + q = 3p \Rightarrow 2p = q$

$\therefore p = \frac{q}{2}$

Corner points of the feasible region determined by the system of linear constraints are (0,3),(1,1) and (3,0) . Let $Z = px + qy$, where $p,$ $q > 0$. Condition on $p$ and $q$, so that the minimum of $Z$ occurs at (3,0) and (1,1) is

So, condition of $p$ and $q$,

so that the minimum of $Z$ occurs at (3,0) and (1,1) is

$p + q = 3p \Rightarrow 2p = q$

$\therefore p = \frac{q}{2}$

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