Verify that ${A^2} = I$, when $A = \left[ {\begin{array}{cccccccccccccccccccc}0&1&{ - 1}\\4&{ - 3}&4\\3&{ - 3}&4\end{array}} \right]$.
Verify that ${A^2} = I$, when $A = \left[ {\begin{array}{cccccccccccccccccccc}0&1&{ - 1}\\4&{ - 3}&4\\3&{ - 3}&4\end{array}} \right]$.
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
We have, $A = \left[ {\begin{array}{cccccccccccccccccccc}0&1&{ - 1}\\4&{ - 3}&4\\3&{ - 3}&4\end{array}} \right]$
$\therefore$ ${A^2} = \left[ {\begin{array}{cccccccccccccccccccc}0&1&{ - 1}\\4&{ - 3}&4\\3&{ - 3}&4\end{array}} \right] \cdot \left[ {\begin{array}{cccccccccccccccccccc}0&1&{ - 1}\\4&{ - 3}&4\\3&{ - 3}&4\end{array}} \right]$
$= \left[ {\begin{array}{llllllllllllllllllll}1&0&0\\0&1&0\\0&0&1\end{array}} \right] = I$
Community Answers (0)
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.