Which of the given values of x and y make the following pair of matrices equal?
$\left[ {\begin{array}{cccccccccccccccccccc}{3x + 7}&5\\{y + 1}&{2 - 3x}\end{array}} \right],\left[ {\begin{array}{cccccccccccccccccccc}0&{y - 2}\\8&4\end{array}} \right]$
• $x = \cfrac{{ - 1}}{3},y = 7$
• Not possible to find
• $y = 7,x = \cfrac{{ - 2}}{3}$
• $x = \cfrac{{ - 1}}{3},y = \cfrac{{ - 2}}{3}$
Which of the given values of x and y make the following pair of matrices equal?
$\left[ {\begin{array}{cccccccccccccccccccc}{3x + 7}&5\\{y + 1}&{2 - 3x}\end{array}} \right],\left[ {\begin{array}{cccccccccccccccccccc}0&{y - 2}\\8&4\end{array}} \right]$
• $x = \cfrac{{ - 1}}{3},y = 7$
• Not possible to find
• $y = 7,x = \cfrac{{ - 2}}{3}$
• $x = \cfrac{{ - 1}}{3},y = \cfrac{{ - 2}}{3}$
Official Solution
.:
(b) $\left[ {\begin{array}{cccccccccccccccccccc}{3x + 7}&5\\{y + 1}&{2 - 3x}\end{array}} \right],\left[ {\begin{array}{cccccccccccccccccccc}0&{y - 2}\\8&4\end{array}} \right]$
$\Rightarrow$ 3x + 7 = 0, y$-$ 2 = 5, y + 1 = 8, 2$-$3x = 4.
Solving first two equations, we get x = $\cfrac{{ - 7}}{3}$ and y = 7
But x = does not satisfy other equation in x.
So, it is not possible to find the required values of x and y.
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