The probability distribution of a discrete random variable X is given below
X 2 3 4 5
P(X) $\frac{5}{k}$ $\frac{7}{k}$ $\frac{9}{k}$ $\frac{{11}}{k}$
The value of $k$ is
The probability distribution of a discrete random variable X is given below
X 2 3 4 5
P(X) $\frac{5}{k}$ $\frac{7}{k}$ $\frac{9}{k}$ $\frac{{11}}{k}$
The value of $k$ is
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
We know that, $\Sigma P(X) = 1$
$\Rightarrow$ $\frac{5}{k} + \frac{7}{k} + \frac{9}{k} + \frac{{11}}{k} = 1$
$\Rightarrow$ $\frac{{32}}{k} = 1$
$\therefore$ $k = 32$
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