If $A$ and $B$ are any two events such that
$P(A) + P(B) - P(A{\rm{ and }}B) = P(A),$ then
(A) $P(B|A) = 1$
(B) $P(A|B) = 1$
(C) $P(B|A) = 0$
(D) $P(A|B) = 0$
If $A$ and $B$ are any two events such that
$P(A) + P(B) - P(A{\rm{ and }}B) = P(A),$ then
(A) $P(B|A) = 1$
(B) $P(A|B) = 1$
(C) $P(B|A) = 0$
(D) $P(A|B) = 0$
Official Solution
Option B is correct
$P(A) + P(B) - P(A \cap B) = P(A)$
$\Rightarrow P(B) - P(A \cap B) = 0$
$\Rightarrow P(A \cap B) = P(B) \Rightarrow \cfrac{{P(A \cap B)}}{{P(B)}} = 1 \Rightarrow P(A/B) = 1$
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