Let $*$ be the binary operation on N given by a$*$ b$=$ L.C.M. of a and b. Find
(i) 5 $*$ 7, 20 $*$ 16
(ii) Is $*$ commutative ?
(iii) Is $*$ associative ?
(iv) Find the identity of $*$ in N
(v) Which elements of N are invertible for the operation $*$ ?
Let $*$ be the binary operation on N given by a$*$ b$=$ L.C.M. of a and b. Find
(i) 5 $*$ 7, 20 $*$ 16
(ii) Is $*$ commutative ?
(iii) Is $*$ associative ?
(iv) Find the identity of $*$ in N
(v) Which elements of N are invertible for the operation $*$ ?
Official Solution
a $*$ b $=$ L.C.M. of a and b.
(i) 5 $*$ 7 $=$ L.C.M. of 5 and 7 $=$ 35
20 $*$ 16 $=$ L.C.M. of 20 and 16 $=$ 80
(ii) a $*$ b $=$ L.C.M. of a and b $=$ L.C.M. of b and a $=$ b $*$ a.
Thus, operation $*$ is commutative.
(iii) a $*$ (b $*$ c) $=$ a $*$ (L.C.M. of b and c)
$=$ L.C.M. of (a and (L.C.M. of b and c))
$=$ L.C.M. of a, b and c.
Similarly, (a $*$ b) $*$ c $=$ (L.C.M. of a and b) $*$ c
$=$ L.C.M. of ((L.C.M. of a and b) and c) $=$ L.C.M. of a, b and c
Thus, a $*$ (b $*$ c) $=$ (a $*$ b ) $*$ c
Hence, the operation $*$ is associative.
(iv) Identity of $*$ in N $=$ 1 because, a $*$ 1
$=$ L.C.M. of a and 1 $=$ 1
(v) Only the element 1 in N is invertible for the operation $*$ because $1 * \cfrac{1}{1} = 1$.
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