If $\overrightarrow {\rm{a}} + \overrightarrow {\rm{b}} + \overrightarrow {\rm{c}} = 0$, then show that $\overrightarrow {\rm{a}} \times \overrightarrow {\rm{b}} = \overrightarrow {\rm{b}} \times \overrightarrow {\rm{c}} = \overrightarrow {\rm{c}} \times \overrightarrow {\rm{a}}$. Interpret the result geometrically.
If $\overrightarrow {\rm{a}} + \overrightarrow {\rm{b}} + \overrightarrow {\rm{c}} = 0$, then show that $\overrightarrow {\rm{a}} \times \overrightarrow {\rm{b}} = \overrightarrow {\rm{b}} \times \overrightarrow {\rm{c}} = \overrightarrow {\rm{c}} \times \overrightarrow {\rm{a}}$. Interpret the result geometrically.
Official Solution
Since, $\quad \vec a + \vec b + \vec c = 0$
$\Rightarrow$ $\vec b = - \vec c - \vec a$
Now, $\vec a \times \vec b = \vec a \times ( - \vec c - \vec a)$
$= \vec a \times ( - \vec c) + \vec a \times ( - \vec a) = - \vec a \times \vec c$
$\Rightarrow$ $\quad \vec a \times \vec b = \vec c \times \vec a$ ……..(i)
Also, $\overrightarrow {\rm{b}} \times \overrightarrow {\rm{c}} = ( - \overrightarrow {\rm{c}} - \overrightarrow {\rm{a}} ) \times \overrightarrow {\rm{c}}$
$= ( - \vec c \times \vec c) + ( - \vec a \times \vec c) = - \vec a \times \vec c$
$\Rightarrow$ $\overrightarrow {\rm{b}} \times \overrightarrow {\rm{c}} = \overrightarrow {\rm{c}} \times \overrightarrow {\rm{a}}$ ……….(ii)
From Eqs. (i) and (ii), $\quad \vec a \times \vec b = \vec b \times \vec c = \vec c \times \vec a$
Geometrical interpretation of the result
If $ABCD$ is a parallelogram such that $\overrightarrow {AB}$
$= \vec a$
and $\overrightarrow {AD} = \vec b$
and these adjacent sides are making angle $\theta$ between each other,
Area of parallelogram $ABCD = |\overrightarrow {\rm{a}} ||\overrightarrow {\rm{b}} ||\sin \theta | = |\overrightarrow {\rm{a}} \times \overrightarrow {\rm{b}} |$
Since, parallelogram on the same base and between the same parallels are equal in area.
We can say that, $\quad |\overrightarrow {\rm{a}} \times \overrightarrow {\rm{b}} | = |\overrightarrow {\rm{a}} \times \overrightarrow {\rm{c}} | = |\overrightarrow {\rm{b}} \times \overrightarrow {\rm{c}} |$
This further implies that, $\overrightarrow {\rm{a}} \times \overrightarrow {\rm{b}} = \overrightarrow {\rm{a}} \times \overrightarrow {\rm{c}} = \overrightarrow {\rm{b}} \times \overrightarrow {\rm{c}}$
So, area of the parallelograms formed by taking any two sides represented by $\overrightarrow {\rm{a}} ,\overrightarrow {\rm{b}}$ and $\overrightarrow {\rm{c}}$
as adjacent are equal.
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