class 12 maths vector algebra

Find a unit vector in the direction of $\overrightarrow {P{\rm{Q}}}$, where $P$ and $Q$ have coordinates (5,0,8) and $(3,3,2)$, respectively.
Since, the coordinates of $P$ and $Q$ are (5,0,8) and (3,3,2) , respectively.

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📘 Vector Algebra NCERT,Exemp,Q.No.3,Page.215 SA

Find a unit vector in the direction of $\overrightarrow {P{\rm{Q}}}$, where $P$ and $Q$ have coordinates (5,0,8) and $(3,3,2)$, respectively.
Since, the coordinates of $P$ and $Q$ are (5,0,8) and (3,3,2) , respectively.

Official Solution

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$\therefore$ $\overrightarrow {PQ} = \overrightarrow {OQ} - \overrightarrow {OP}$

$= (3\widehat {\rm{i}} + 3\widehat {\rm{j}} + 2\widehat {\rm{k}}) - (\widehat {\rm{i}} + 0\widehat {\rm{j}} + 8\widehat {\rm{k}})$

$= - 2\widehat {\rm{i}} + 3\widehat {\rm{j}} - 6\widehat {\rm{k}}$

$\therefore$

Unit vector in the direction of $\overrightarrow {{\rm{PQ}}} = \frac{{\overrightarrow {{\rm{PQ}}} }}{{|\overrightarrow {{\rm{PQ}}} |}} = \frac{{ - 2\widehat {\rm{i}} + 3\widehat {\rm{j}} - 6\widehat {\rm{k}}}}{{\sqrt {{2^2} + {3^2} + {6^2}} }}$

$= \frac{{ - 2\widehat {\rm{i}} + 3\widehat {\rm{j}} - 6\widehat {\rm{k}}}}{{\sqrt {49} }}$

$= \frac{{ - 2\widehat {\rm{i}} + 3\widehat {\rm{j}} - 6\widehat {\rm{k}}}}{7}$

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