Show that the vector $\hat i + \hat j + \hat k$ is equally inclined to the axes $OX,OY$ and $OZ$.
Show that the vector $\hat i + \hat j + \hat k$ is equally inclined to the axes $OX,OY$ and $OZ$.
Official Solution
Let $\vec a = \hat i + \hat j + \hat k$
$\therefore$
Direction-cosines of $\vec a$ are
$< \cfrac{1}{{\sqrt {1 + 1 + 1} }}$ , $\cfrac{1}{{\sqrt {1 + 1 + 1} }},\cfrac{1}{{\sqrt {1 + 1 + 1} }} >$
i.e., $< \cfrac{1}{{\sqrt 3 }},\cfrac{1}{{\sqrt 3 }},\cfrac{1}{{\sqrt 3 }} >$
Hence the given vector is equally inclined to the axes $OX,OY$ and $OZ$.
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