Let the vectors $\vec a$ and $\vec b$ be such that $|\vec a| = 3$ and $|\vec b| = \cfrac{{\sqrt 2 }}{3}$, then $\vec a \times \vec b$ is a unit vector, if the angle between $\vec a$and $\vec b$ is
• $\pi /6$
• $\pi /4$
• $\pi /3$
• $\pi /2$
Let the vectors $\vec a$ and $\vec b$ be such that $|\vec a| = 3$ and $|\vec b| = \cfrac{{\sqrt 2 }}{3}$, then $\vec a \times \vec b$ is a unit vector, if the angle between $\vec a$and $\vec b$ is
• $\pi /6$
• $\pi /4$
• $\pi /3$
• $\pi /2$
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
{Correct Option is b}
$|\vec a \times \vec b| = |\vec a||\vec b|\sin \theta$
$\Rightarrow 1 = (3)\left( {\cfrac{{\sqrt 2 }}{3}} \right)\sin \theta \Rightarrow \sin \theta = \cfrac{1}{{\sqrt 2 }} \Rightarrow \theta = \cfrac{\pi }{4}$
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