class 12 maths vector algebra

Area of a rectangle having vertices $A,B,C$ and $D$ with position vectors
$- \hat i + \cfrac{1}{2}\hat j + 4\hat k,\,\,\,\hat i + \cfrac{1}{2}\hat j + 4\hat k,\,\,\,\hat i - \cfrac{1}{2}\hat j + 4\hat k$ and $- \hat i - \cfrac{1}{2}\hat j + 4\hat k$ respectively is

• $\cfrac{1}{2}$

• $1$

• $2$

• $4$

VAVidaara Admin Asked 9d ago 0 views 0 answers
📘 Vector Algebra NCERT,Page 454,Ex.10.4,Q.No 12 SA

Area of a rectangle having vertices $A,B,C$ and $D$ with position vectors
$- \hat i + \cfrac{1}{2}\hat j + 4\hat k,\,\,\,\hat i + \cfrac{1}{2}\hat j + 4\hat k,\,\,\,\hat i - \cfrac{1}{2}\hat j + 4\hat k$ and $- \hat i - \cfrac{1}{2}\hat j + 4\hat k$ respectively is

• $\cfrac{1}{2}$

• $1$

• $2$

• $4$

Official Solution

VVidaara Team ✓ Verified solution NCERT & Exemplar

{Correct Option is c}

Here, $\overrightarrow {AB} = (\hat i + \cfrac{1}{2}\hat j + 4\hat k) - ( - \hat i + \cfrac{1}{2}\hat j + 4\hat k) = 2\hat i$
$\Rightarrow |\overrightarrow {AB} | = 2$

and $\overrightarrow {AD} = ( - \hat i - \cfrac{1}{2}\hat j + 4\hat k) - ( - \hat i + \cfrac{1}{2}\hat j + 4\hat k) = - \hat j$

$\Rightarrow |\overrightarrow {AD} | = 1$
$\Rightarrow$ Area of rectangle

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