Show that the direction cosines of a vector equally inclined to the axes $OX,OY$ and $OZ$ are$\cfrac{1}{{\sqrt 3 }},\cfrac{1}{{\sqrt 3 }},\cfrac{1}{{\sqrt 3 }}$.
Show that the direction cosines of a vector equally inclined to the axes $OX,OY$ and $OZ$ are$\cfrac{1}{{\sqrt 3 }},\cfrac{1}{{\sqrt 3 }},\cfrac{1}{{\sqrt 3 }}$.
Official Solution
Let a vector makes $\alpha ,\beta ,\gamma$ angles with axes $OX,OY\,\,{\rm{and}}\,\,OZ$ respectively.
As it is equally inclined to axes,
So, $\alpha = \beta = \gamma$
Now we have
${\cos ^2}a + {\cos ^2}\beta + {\cos ^2}\gamma = 1$
$\Rightarrow 3{\cos ^2}\alpha = 1$
$\Rightarrow {\cos ^2}\alpha = \cfrac{1}{3} \Rightarrow \cos \alpha = \pm \cfrac{1}{{\sqrt 3 }}$
$\therefore$
Direction cosines of the vector are $< \cfrac{1}{{\sqrt 3 }}\cfrac{1}{{\sqrt 3 }}\cfrac{1}{{\sqrt 3 }} > + ve\,\,{\rm{sign}}$.
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