For 0<x< 4, 2x- 2x equals (a) tan(x- 4) (b) tan( 4-x) (c) tan(x+ 4) (d) tan²(x+ 4)

Correct answer: (b) tan( 4-x) 2x- 2x=(1- 2x)/( 2x)=((cos x-sin x)²)/(cos²x-sin²x)=(cos x-sin x)/(cos x+sin x)=tan ! ( 4-x ). JEE Advanced 1994 · Trigonometry — verified solution by the Vidaara Team.

JEE PYQ

[JEE Advanced 1994] For $0<x<\frac\pi4$, $\sec2x-\tan2x$ equals

VAVidaara Admin Asked 1mo ago 3 views 1 answer

#PYQJEE #JEE #JEE Advanced #1994 #trig-identities #Trigonometry

For $0<x<\frac\pi4$, $\sec2x-\tan2x$ equals

(a) $\tan(x-\frac\pi4)$
(b) $\tan(\frac\pi4-x)$
(c) $\tan(x+\frac\pi4)$
(d) $\tan^2(x+\frac\pi4)$

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 1mo ago ▲ 0

Correct answer: (b) $\tan(\frac\pi4-x)$

$\sec2x-\tan2x=\frac{1-\sin2x}{\cos2x}=\frac{(\cos x-\sin x)^2}{\cos^2x-\sin^2x}=\frac{\cos x-\sin x}{\cos x+\sin x}=\tan\!\left(\frac\pi4-x\right).$

JEE Advanced 1994 · Trigonometry — verified solution by the Vidaara Team.

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