If x+iy= a+ib c+id, prove that (x²+y²)²= a²+b² c²+d².

Answer: Proved. Taking modulus: x²+y²=|x+iy|²= |(a+ib)/(c+id) |^1/2·2 ! !/ ,... — precisely x²+y²=√((a²+b²)/(c²+d²)); squaring gives (x²+y²)²=(a²+b²)/(c²+d²). JEE Advanced 1979 · Complex Numbers — verified solution by the Vidaara Team.

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[JEE Advanced 1979] if x iy sqrt a ib c id prove that x 2 y 2

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If $x+iy=\sqrt{\dfrac{a+ib}{c+id}}$, prove that $(x^2+y^2)^2=\dfrac{a^2+b^2}{c^2+d^2}$.

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VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2d ago ▲ 0

Answer: Proved.

Taking modulus: $x^2+y^2=|x+iy|^2=\left|\frac{a+ib}{c+id}\right|^{1/2\cdot2}\!\!/\,...$ — precisely $x^2+y^2=\sqrt{\frac{a^2+b^2}{c^2+d^2}}$; squaring gives $(x^2+y^2)^2=\frac{a^2+b^2}{c^2+d^2}$.

JEE Advanced 1979 · Complex Numbers — verified solution by the Vidaara Team.

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