The equation of the tangent to the curve x = a cos³ θ, y = a sin³ θ at θ = π/4 is:
The equation of the tangent to the curve x = a cos³ θ, y = a sin³ θ at θ = π/4 is:
- A. x + y = a/√2
- B. x − y = a/√2
- C. x + y = a√2
- D. x − y = a√2
Answer: A) x + y = a/√2
Explanation: dx/dθ = −3a cos² θ sin θ, dy/dθ = 3a sin² θ cos θ. dy/dx = −tan θ. At θ = π/4, slope = −1. Point: x = a(1/√2)³ = a/(2√2), y = a/(2√2). Tangent: y − y₁ = −1(x − x₁) → x + y = 2 × a/(2√2) = a/√2.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.