The normal at the point (1, 1) on the curve 2y + x² = 3 is:

The normal at the point (1, 1) on the curve 2y + x² = 3 is:

• A. x + y = 2
• B. x − y = 0
• C. x + y = 0
• D. x − y = 2

Answer: A) x + y = 2

Explanation: 2y = 3 − x² → y = (3 − x²)/2. dy/dx = −x. At (1, 1), slope of tangent = −1. Slope of normal = 1. Eq: y − 1 = 1(x − 1) → y = x → x − y = 0. That's option B. So correct is x − y = 0, index 1. Actually, We'll keep options as given and set correct index to 1.