The equation of the normal to the curve y = |x² − 4| at the point where x = 1 is:

The equation of the normal to the curve y = |x² − 4| at the point where x = 1 is:

• A. 2y − x = 5
• B. 2y + x = 7
• C. y + 2x = 5
• D. y − 2x = 1

Answer: A) 2y − x = 5

Explanation: At x = 1, y = |1 − 4| = 3 and (since x² − 4 < 0) y = 4 − x², so dy/dx = −2x = −2. Normal slope = 1/2: y − 3 = (1/2)(x − 1) ⇒ 2y − x = 5.